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Bess [88]
2 years ago
5

9. Which of the following are true for all regular languages and all homomorphisms? (a) h (L1 ∪ L2)= h (L1) ∩ h (L2). (b) h (L1

∩ L2)= h (L1) ∩ h (L2). (c) h (L1L2) = h (L1) h (L2).
Computers and Technology
1 answer:
mixer [17]2 years ago
5 0

Answer:

h (L1 ∪ L2)= h (L1) ∩ h (L2).

This is true.

There will be w ∈  (L1 ∪ L2) for any s ∈ h (L1 ∪ L2) in such a way that s=h(w)

we can assume that w ∈ L1

So In this case h(w) ∈ L (S1). Hence s ∈ L(S1)

for any s ∈ h (L1) U h(L2)

We can assume that s ∈ L(S1)

There exists w ∈ L1 such that s= h(w)

In this case it is w ∈ L1 U L2 as well.

Hence , s ∈ h (L1 U L2)

Explanation

consider  = 0,1 and  = a,b and h(0) = a , h(1) = ab

(a) Consider L1 = 10,01 and L2 = 00,11

   Now L1 ∪ L2 = 00,01,10,11

   h (L1 ∪ L2) = h(00) , h(01) , h(10) , h(11) = h(0)h(0) , h(0)h(1) , h(1)h(0) , h(1)h(1)

  = aa, aab , aba , abab

Hence h (L1 ∪ L2) = aa, aab , aba , abab .

Here h (L1) = h(10) , h(01) = h(1)h(0) , h(0)h(1) = aba , aab

Hence h (L1) = aba , aab .

Here h (L2) = h(00) , h(11) = h(0)h(0), h(1)h(1) = aa, abab

Hence h(L2) = aa, abab.

Finally Hence , h (L1 ∪ L2)= h (L1) ∩ h (L2).

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8 0
2 years ago
Row array gameScores contains all player scores. Construct a row array highScores than contains all player scores greater than m
Sever21 [200]

Answer:

The solution is written using Python as it has a simple syntax.

  1. def getHighScores(gameScores, minScore):
  2.    meetsThreshold = []
  3.    for score in gameScores:
  4.        if(score > minScore):
  5.            meetsThreshold.append(score)
  6.    return meetsThreshold
  7. gameScores = [2, 5, 7, 6, 1, 9, 1]
  8. minScore = 5
  9. highScores = getHighScores(gameScores, minScore)
  10. print(highScores)

Explanation:

Line 1-8

  • Create a function and name it as <em>getHighScores</em> which accepts two values, <em>gameScores</em> and <em>minScore</em>. (Line 1)
  • Create an empty list/array and assign it to variable <em>meetsThreshold</em>. (Line 2)
  • Create a for loop to iterate through each of the score in the <em>gameScores</em> (Line 4)
  • Set a condition if the current score is bigger than the <em>minScore</em>, add the score into the <em>meetsThreshold</em> list (Line 5-6)
  • Return <em>meetsThreshold</em> list as the output

Line 11-12

  • create a random list of <em>gameScores</em> (Line 11)
  • Set the minimum score to 5 (Line 12)

Line 13-14

  • Call the function <em>getHighScores()</em> and pass the<em> gameScores</em> and <em>minScore </em>as the arguments. The codes within the function <em>getHighScores()</em>  will run and return the <em>meetsThreshold </em>list and assign it to <em>highScores.</em> (Line 13)
  • Display <em>highScores</em> using built-in function print().
8 0
2 years ago
You would like the user of a program to enter a customer’s last name. Write a statement thaUse the variables k, d, and s so that
mojhsa [17]

Answer:

1st question:

Use the variables k, d, and s so that they can read three different values from standard input an integer, a float, and a string respectively. On one line, print these variables in reverse order with exactly one space in between each. On a second line, print them in the original order with one space in between them.

Solution:

In Python:

k = input()  #prompts user to input value of k i.e. integer value

d = input()  #prompts user to input value of d i.e. float value

s = input()  #prompts user to input value of s i.e. a string

print (s, d, k)  #displays these variable values in reverse order

print (k, d, s)#displays these variable values in original order

In C++:

#include <iostream>    // to use input output functions

using namespace std;   //to identify objects like cin cout

int main() {    //start of main function

  int k;   //declare int type variable to store an integer value

  float d; //  declare float type variable to store a float value

  string s;   //  declare string type variable to store an integer value

  cin >> k >> d >> s;    //reads the value of k, d and s

  cout << s << " " << d << " " << k << endl;     //displays these variables values in reverse order

  cout << k << " " << d << " " << s << endl;   } // displays these variable values in original order

Explanation:

2nd question:

You would like the user of a program to enter a customer’s last name. Write a statement that asks user "Last Name:" and assigns input to a string variable called last_name.

Solution:

In Python:

last_name = input("Last Name:")

# input function is used to accept input from user and assign the input value to last_name variable

In C++:

string last_name;  //declares a string type variable named last_name

cout<<"Last Name: ";  // prompts user to enter last name by displaying this message Last Name:

cin>>last_name; // reads and assigns the input value to string variable last_name

The programs alongwith their outputs are attached.

6 0
2 years ago
Create a single list that contains the following collection of data in the order provided:
ivann1987 [24]

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

8 0
2 years ago
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