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Paha777 [63]
2 years ago
15

Using a little bit of algebra, prove that (4.2) is equivalent to (4.3). In other words, the logistic function representation and

logit representation for the logistic regression model are equivalent.
Mathematics
1 answer:
ki77a [65]2 years ago
7 0

Answer:

The logistic function representation and logic representation for the logistic regression model are equivalent.

Step-by-step explanation:

Y(X)=e ^(B 0 +B 1)/  (1+e^( B 0 +B1x)) .... 4.2

P(x)/(1−P(x))=e^( B 0 +B 1x) .... 4.3

Let

Y(X)=e^ (B 0 +B1x)

1/p(X)=1+e^( B 0 +B1x)

P(x)=Y(x)/(1+Y(x))

P(x)(1+Y(x))=Y(x)

Expanding;

P(x)+P(x)Y(x)=Y(x)

P(x)=Y(x)−P(x)Y(x)

P(x)=Y(x)(1−P(x))

P(x)/(1−P(x)) =Y(x)

P(x)/(1−P(x))=e^( B 0 +B 1x)

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2 years ago
Isla is dividing 3x3 + x2 - 12x - 4 by x + 2 using a division table.
maria [59]

A. A = -10 x, B = -4

<u>Explanation:</u>

Given:

For A:

The Quotient of the Operation is -5 x

The Divisor of the Operation is 2

So the remainder is -10 x

For B:

The Quotient of the Operation is -2

The Divisor of the Operation is +2

So the remainder is -4

So, the missing values in the table is A = -10 x and B = -4

3 0
2 years ago
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The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in
Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
2 years ago
Mr. James has cylindrical beakers that measure 4 inches in diameter and are 9 inches high. What is the volume contained within t
kirill115 [55]
The equation to find the volume of a cylinder is V = pi•r^2•h.
The radius is half of the diameter.  Since Mr. James' beakers have a diameter of 4, their radius would be 2.  2 squared is 4.
Their height is 9 inches.
V = 3.14•4•9
V = 3.14•36
V = 113.04
The answer is C, or 113.04 cubic inches.
5 0
2 years ago
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Laura has $1000 bond with a 3.4% coupon. Laura purchased this bond for $1065. What is the yield of this new bond?
inn [45]

Answer:

The answer is B.

Step-by-step explanation:

8 0
2 years ago
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