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Nikitich [7]
2 years ago
9

Stephen evaluated (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). His work is shown below

. Which two statements describe the errors Stephen made? (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). (6.34 times 4.5) (10 Superscript negative 7 Baseline times 10 Superscript 3 Baseline). 28.53 times 10 Superscript negative 4 Baseline. Negative 28.53 times 10 Superscript 4 Baseline. Negative 2.853 times 10 Superscript 3 Baseline.
Mathematics
2 answers:
Maksim231197 [3]2 years ago
7 0

Answer:

The step 4 and 5 describe the errors Stephen made.

Step-by-step explanation:

Given : Stephen evaluated (6.34\times 10^{-7})(4.5\times 10^3).  His work is shown below.

To find : Which two statements describe the errors Stephen made?

Solution :

Step 1 - (6.34\times 10^{-7})(4.5\times 10^3)

Step 2 - (6.34\times 4.5)(10^{-7}\times 10^3)

Step 3 - (28.53)(10^{-4})

Step 4 - 28.53\times 10^{4}

Error is the step as 4 sign is negative.

So correct step is 28.53\times 10^{-4}

Step 5 - 28.53\times 10^{3}

Error is the step as there is 4 in place of 3.

So correct step is 28.53\times 10^{-4}

The step 4 and 5 describe the errors Stephen made.

Zielflug [23.3K]2 years ago
4 0

Answer:

D and E

Step-by-step explanation:

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Step-by-step explanation:

We would first convert meters to centimeters.  There are 100 cm in a meter; this means 3.5 m = 3.5(100) = 350 cm.

The ratio of the height to base of the model is 10/22.  The ratio of the playhouse would then be x/350.  This gives us

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Step-by-step explanation:

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In the graph attached,

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Therefore, the new function of above translation will be,

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If we rewrite the function in the form of an equation, graph will be represented by

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Answer:

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<u>Total displacement = 24 m</u>

Step-by-step explanation:

<u>Distance and Displacement</u>

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dtotal=d1+d2+d3+...+dn

This sum is obtained independently of the direction the object moves.

The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.

For the question at hand, it's not known if the requirement is about the distance or the displacement, so we will compute both.

To compute the distance, we just add all the distances:

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To compute the displacement, we must establish a positive direction as desired. Let's choose the east as the positive direction. Any movement eastward is considered positive and any movement westward is negative. We mentioned the displacement is a vector, but since we only have movement in the x-axis, we can only manage the signs. Thus, the total displacement is:

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