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Cerrena [4.2K]
2 years ago
9

Kylie needs to pack her baton for a color-guard competition. The baton is 38 inches long. Will it fit in a rectangular box with

a base of 13 inches by 35 inches and height of 13 inches?
Mathematics
1 answer:
jonny [76]2 years ago
8 0

Answer:

NO

Step-by-step

No. 38 inches can't fit in 35 inch long box.

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Solve 3x2 + 18x + 15 = 0 by completing the square. 3(x + 3)2 = 6; x = −3 + square root 2, x = −3 − square root 2 3(x + 9)2 = 12;
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3(x + 3)2 = 12; x = -5, x = -1
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A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

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Jerry takes trail max on Hikes. a package of dried apricots weighs 49.5 ounces. a package of sunflower seeds weighs 45 ounces. J
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2 years ago
Benito and Tyler are painting opposite sides of the same fence. Tyler has already painted 19 ½ feet of his side of the fence whe
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Answer:

Part A: The time it will take for both of them to painted equal number of feet is 4.875 minutes

The number of feet Benito will have painted when the two sides have equal length is 73.125 feet

Part B: It is not true that Tyler will finish painting his side of the fence before Benito finishes painting his

Part C: Time to rest is 1.864 minutes

Step-by-step explanation:

The given information are;

The length of fence Tyler already painted when Benito started = 19 ¹/₂ feet

Benito paints 15 feet/minute

Tyler paints 11 feet/minute

Length of fence = 150 feet

Part A:

The time it will take for both of them to painted equal number of feet is given as follows;

11×t + 19.5 = 15×t

4×t = 19.5

t = 19.5/4= 4.875 minutes

The time it will take for both of them to painted equal number of feet = 4.875 minutes

The length Benito will have painted when the two sides have equal length = 15 × 4.875 = 73.125 feet

Part B: The time it will take Tyler to finish painting his side of the fence is given as follows;

11 × t + 19.5 = 150

t = (150 - 19.5)/11 ≈ 11.864 minutes

While the time it will take Benito to finish painting his side of the fence is given as follows;

15 × t  = 150

t = 150/15 ≈ 10 minutes

Therefore it is not true that Tyler will finish painting his side of the fence before Benito finishes painting his

Part C: Given that Benito finishes before Tyler, the length of time Benito gets to rest is given as follows;

Time to rest = Time Tyler takes to finish - Time Benito takes to finish

Time to rest = 11.864 - 10 = 1.864 minutes.

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If you spend 780 minutes per year waiting at traffic lights, how many hours is this?
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Answer:
That will me 13 hours
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2 years ago
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