Answer:
Step-by-step explanation:
A dime is worth 10 cents. Converting to dollars, it becomes 10/100 = $0.1
A quarter is worth 25 cents. Converting to dollars, it becomes 25/100 = $0.25
Let x represent the number of dimes that Jayden has.
Let y represent the number of quarters that Jayden has.
Jayden has some dimes and some quarters. He has at most 25 coins. It means that
x + y ≤ 25
The coins worth at least $4.60 combined. It means that
0.1x + 0.25y ≥ 4.6 - - - - - - - - - - 1
If Jayden has 7 dimes, then
7 + y ≤ 25
y ≤ 25 - 7
y ≤ 18
Substituting x = 7 into equation 1, it becomes
0.1 × 7 + 0.25y ≥ 4.6
0.7 + 0.25y ≥ 4.6
0.25y ≥ 4.6 - 0.7
0.25y ≥ 3.9
y ≥ 3.9/0.25
y ≥ 15.6
All possible values for the number of quarters that he could have would be
15.6 ≤ y ≤ 18
C=Pi X D
Diameter is twice the radius so that would be 24 feet
C = Pi X 24
C = (22/7) X 24
C = 75.428 Feet.
Answer:
$1.60
$2.88
Step-by-step explanation:
To find the selling price of the distributor and the retailer, we first need to find how much the distributor sells each pack of cards.
To find the selling price we use the formula.
Selling Price = Cost + Markup
Cost = $0.80
Markup rate = 100% or 1
Selling Price = 0.80 + (0.80*1)
Selling Price = $1.60
So the distributor sells each pack of cards at $1.60 to the retailer.
Now to find the selling of the retailer, we need to use the selling price of the distributor.
Cost = $1.60
Markup rate = 80% or 0.80
Selling price = 1.60 + (1.60 * 0.80)
Selling price = $2.88
So the retailer sells each pack of cards at $2.88 to the customers.
Answer:
f(x) = 3(2)^x
Step-by-step explanation:
The Table is:
<u>x</u> <u>f(x)</u>
-2 3/4
-1 3/2
0 3
1 6
2 12
The exponential funtion has the next form:
f(x) = a(b)^x
At x = 0, f(x) = a. Then, a = 3
Isolating b from the equation:
f(x)/a = b^x
ln(f(x)/a) = x*ln(b)
[ln(f(x)/a)]/x = ln(b)
At x = 1, f(x) = 6. Then:
[ln(6/3)]/1 = ln(b)
ln(2) = ln(b)
2 = b
Therefore, the function is f(x) = 3(2)^x
Answer:
279 silvery minnow
Step-by-step explanation:
Number of Silvery Minnows initially tagged = 54
Number of minnows captured = 62
Number of tagged minnows in captured ones = 12
Remember that in the very beginning there were no tagged minnows. 54 minnows were captured, tagged and released. This means, there are total 54 tagged minnows in the entire population. Lets say there are x number of minnows in total.
So, in x minnows, 54 are tagged ones.
When 62 minnows are captured, only 12 are tagged ones and remaining are un-tagged. Since, the minnows were randomly captured, we can develop a proportion from this case to estimate the total population of minnows in the Rio Grande River.
Ratio of tagged minnows to total population must be equal to the ratio of captured tagged minnows in total captured minnows.
i.e.
This means, there were 279 silvery minnows in the Rio Grande River.
