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IgorLugansk [536]
2 years ago
4

A company can manufacture a product using hand tools. Tools will cost $1,000, and the manufacturing cost per unit will be $1.50.

As an alternative, an automated system will cost $15,000 with a manufacturing cost per unit of $0.50. If the anticipated annual volume is 5,000 units and interest is neglected, the payback period (yrs) to buy the automated system rather than the hand tool method is most nearly:
A. 2.8
B. 3.6
C. 15.0
D. never
Business
2 answers:
Cerrena [4.2K]2 years ago
5 0

Answer:

A) 2.8

Explanation:

Ksenya-84 [330]2 years ago
5 0

Answer:

A.2.8

Explanation:

guess in order to break even, the two alternatives has toequal so:

t=time (year):

so:

first choice

$1500 -fixed

$1.50 per unit which equal to $1.50*5000=$7500 per year

alternative

$15,000 -fixed

$0.50 per unit which equals to $0.50*5000=$2500 per year

so:

t=2.8 years.

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Answer:

CODE

import time #importing time module

import math #importing math module

pi = math.pi #defining the value of pi

u = 70 #initial velocity

g = 9.8 #gravitational acceleration

time_step = 0.01 #time step of 0.01 secs

time_elapsed = 0.0

maxAngle = 0

angle = 1

h = 5.0 #setting the initial height to to 5m

x = 0.0

maxRange = 0.0

for angle in range(1,91): #loop which angle takes value from 1 to 90

ux = u * math.cos((pi / 180) * angle) #velocity in x axis

uy = u * math.sin((pi / 180) * angle) #velocity in y axis

for i in range(1000): #running for 1000 steps

dragx = 0.5 * 1.225 * 1.4 * 0.8 * ux * ux #calculating the drag in x direction

dragy = 0.5 * 1.225 * 1.4 * 0.8 * uy * uy #calculating the drag in y direction

drag_ax = dragx / 65.0 #calculating drag acceleration in x axis

drag_ay = dragy / 65.0 #calculating drag acceleration in y axis

accelx = drag_ax #resultant acceleration in x axis

accely = g + drag_ay #resultant acceleration in y axis

vx = ux - accelx * time_step #velocity in the x axis at any instant

vy = uy - accely * time_step #velocity in the y axis at any instant

h += uy * time_step - 0.5 * accely * time_step * time_step #height at any instant of the projectile

x += ux * time_step - 0.5 * accelx * time_step * time_step #range at any instant in the x axis of the projectile

print("Height " + str(h) + " Range " + str(x)) #printing the current position

time.sleep(time_step) #waiting for 0.01 secs

time_elapsed += time_step #calculating the time elapsed

ux = vx #setting the final velocitites to new initial velocities

uy = vy

if h <= 0.0: #if a height 0 is reached

if x > maxRange:

maxRange = x #max angles are noted

maxAngle = angle

h = 5.0 #variables are initialized

x = 0.0

u = 70.0

vx = 0.0

vy = 0.0

print("Wait till the next simulation starts.....")

time.sleep(10.0 - time_elapsed) #wait for 10 secs

time_elapsed = 0.0

break

print("The optimum angle for for Callista is {} degrees which will give her a range of {} metres".format(str(maxAngle),str(maxRange))) #the optimum angle is printed

Explanation:

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