Answer: $1,500
Explanation:
The future value of value using simple interest is:
Future value = Value * ( 1 + rate * time)
2,400 = Value * (1 + 15% * 4)
2,400 = Value * 1.6
Value = 2,400 / 1.6
Value = $1,500
Answer:
There is a need for some people to see the total transparency of the records that are meant to be shared with a select group of people. There are certain things that can be done for this. The first one is that the sharing rules should be checked. To whom are the details shared with. The next one is the filters that are used.
These can be reported and changed accordingly. Lastly, the whole organization’s defaults can be checked. This is something that can be done when the previous methods that were done did not work that well. Once some changes are done, the people can check if they already work and if the records can be viewed.
Explanation:
Answer:
See the components in explaination
Explanation:
In order to make it as IPv6, few key components should be supported, those components are given below:
The infrastructure must support the enhanced protocol StateLess Address Auto-Configuration (SLAAC).
Static addressing with DHCPv6, dynamic addressing with DHCPv6 and SLAAC are the methods used to configure the IPv6. The network administrator should able to understand and implement the IPv6 through the DHCPv6.
Other than the implementation, working of IPv4 and IPv6 are same. Therefore, the administrator need not to learn new information for its working.
As the IPv6 address length is 128-bit and purpose is for everything on line to have an IP address. It must allow the internet to expand faster devices to get internet access quickly.
The DHCPv6 is not supported by all windows. Therefore, network administrator should check the corresponding Operating system (OS) would support the DHCPv6 for IPv6.
The network administrator must have good knowledge and skills on the IPv6.
The above mentioned key components should be verified by the network administrator in order to support for IPv6 project with DHCPv6.
Answer:g
public static int addOddMinusEven(int start, int end){
int odd =0;
int even = 0;
for(int i =start; i<end; i++){
if(i%2==0){
even = even+i;
}
else{
odd = odd+i;
}
}
return odd-even;
}
}
Explanation:
Using Java programming language:
- The method addOddMinusEven() is created to accept two parameters of ints start and end
- Using a for loop statement we iterate from start to end but not including end
- Using a modulos operator we check for even and odds
- The method then returns odd-even
- See below a complete method with a call to the method addOddMinusEven()
public class num13 {
public static void main(String[] args) {
int start = 2;
int stop = 10;
System.out.println(addOddMinusEven(start,stop));
}
public static int addOddMinusEven(int start, int end){
int odd =0;
int even = 0;
for(int i =start; i<end; i++){
if(i%2==0){
even = even+i;
}
else{
odd = odd+i;
}
}
return odd-even;
}
}
