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bogdanovich [222]
2 years ago
8

What is the volume, in cubic cm, of a cylinder with a height of 8cm and a base radius of 7cm, to the nearest tenths place?

Mathematics
1 answer:
FromTheMoon [43]2 years ago
7 0

Answer:

Volume of the cylinder =  1230.88\,cm^3

Step-by-step explanation:

Height(h) of the cylinder = 8 cm

Radius(r) of the base= 7cm

Volume of a cylinder is:

                  = \pi \times r^2\times h

As,

   \pi =\dfrac{22}{7} = 3.14

Putting the values in the formula:

Volume is:

           =3.14\times(7\times7)\times8\\\\=3.14\times49\times8\\\\=3.14\times392\\\\=1230.88\,cm^3

The volume of the cylinder is :  1230.88\,cm^3

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jek_recluse [69]
You move to the right, so the exponent is gonna be negative.
1.21 * 10-²
6 0
2 years ago
Find the length of side AB<br> Give answer to 3 significant figures
Rina8888 [55]

Answer:

AB = 8.857 cm

Step-by-step explanation:

Here, we are given a <em>right angle</em> \triangle ABC in which we have the following things:

\angle A = 90 ^\circ\\\angle C = 41 ^\circ\\\text{Side }BC = 13.5 cm

Side <em>BC </em>is the hypotenuse here.

We have to find the side <em>AB</em>.

Trigonometric functions can be helpful to find the value of Side AB here.

Calculating \angle B:

Sum of all the angles in \triangle ABC is 180^\circ.

\Rightarrow \angle A + \angle B + \angle C = 180^\circ\\\Rightarrow 90^\circ + \angle B + 41^\circ = 180^\circ\\\Rightarrow \angle B = 49^\circ

We know that <em>cosine </em>of an angle is:

cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}\\\Rightarrow cos B = \dfrac{AB}{BC}\\\Rightarrow cos 49^\circ = \dfrac{AB}{13.5}\\\Rightarrow AB = 13.5 \times 0.656\\\Rightarrow AB = 8.857 cm

So, side AB = 8.857 cm .

6 0
2 years ago
Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.
s344n2d4d5 [400]

Answer:

The width of lot B is 11 feet, so option A is correct.

Step-by-step explanation:

Given:

  • Two rectangular properties share a common side.  
  • Lot A is 33 feet wide and 42 feet long.  
  • The combined area of the lots = 1,848 square feet.  

To find:

How many feet wide is Lot B?  

Solution:

we know that, area of a rectangle is length x breadth

Then area of lot A = 33 x 42 = 1386 square feet.

And area of lot B = width x 42

Now, we are given that, total area = 1848  

area of lot A + area of lot B = 1848  

1386 + width x 42 = 1848  

width x 42 = 1848 – 1386  

width x 42 = 462  

width =\frac{42}{462}

width = 11

Hence, the width of lot B is 11 feet, so option A is correct.

7 0
2 years ago
A candle is placed 22 cm from a converging mirror. An upright image is produced and is located 53 cm behind the mirror. What is
Hatshy [7]

Answer:

2.41

Step-by-step explanation:

Magnifcation = Image distance/object distance

Given;

Image distance = -53cm

Object distance = 22cm

Substitute

Magnification = 53/22

Magnification = 2.41

Note that the negative sign is not used in calculating magnification

7 0
1 year ago
Matt and Shirley, working together, can rake the yard in 10 hours. Working alone, Shirley takes twice as long as Matt. How long
AysviL [449]
5 hours  is the answer
4 0
2 years ago
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