Since q+d=19, we can re-write this as d=19-q. Using the second equation 0.25q+0.1d=4 we can multiply both sides by 100. So we get 25q+10d=400. So now we can plug d=19-q into 25q+10d=400. So now we get, 25q+190-10q=400. Subtracting both sides by 190, we get 15q=210 and that q=14 plugging that in d=5

notice the picture of the graph added here
low and behold, x = -17, y is 0, and x= 15, y is 0
the graph is touching the x-axis, an x-intercept
or so-called, a "solution"
Answer: Ken Should have moved 9 units to the right because his prediction for May is 9°C. Moving to the left part of the number line would take Ken into negative degrees. 9°C is warmer than 7°C. Therefore, Ken should have moved 9 units to the right of the number line instead of 2 units to the left.
Step-by-step explanation:
Answer:
Step-by-step explanation:
x² + b²/4a² = -c / a + b²/4a²
x² + (b/2a)² = -c/a + (b/2a)²
(x + b/2a)² = -c/a + (b/2a)² = -c / a + b²/4a² = (-4ac+ b²)/4a²
(x + b/2a)² = (-4ac+ b²)/4a²
√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}
x + b/2a = √(-4ac+ b²) / √(4a²) = √(-4ac+ b²) / 2a = √( b²-4ac) / 2a
x + b/2a = √( b²-4ac) / 2a
- subtract b/2a from both sides
x + b/2a -b/2a = {√( b²-4ac) / 2a } -b/2a
x = -b/2a + {√( b²-4ac) / 2a }
x = {-b±√( b²-4ac)}/2a
Step-by-step explanation:
To prove that △VWZ ~ △YXZ by SAS theorem, we must prove that two of the sides for each triangle is congruent, and the angle inbetween the sides are congruent. Depending on which side is given to you, choose the one that conforming to it. For example:
Figure 1:
Side HJ is congruent with side ML, Angle J is congruent with angle M, Side IJ is congruent with side KM (SAS)
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