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konstantin123 [22]
2 years ago
6

Paul, Colin and Brian are waiters.

Mathematics
1 answer:
amid [387]2 years ago
3 0

Answer: 3 parts more

Step-by-step explanation:

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Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

6 0
2 years ago
Read 2 more answers
Fill in the blank. In the triangle below, y=__. Round your answer to two decimal places.
Kobotan [32]
To solve this we use trigonometric functions that would relate the hypotenuse y and the given values. For this case we use cosine function which is expressed as:

cosine theta = adjacent side / hypotenuse
cosine 52 = 35 / y
y = 35 / cos 52
y = 56.85
7 0
2 years ago
Read 2 more answers
This star is made up of 4 equilateral triangles of equal area and a square.
pentagon [3]

Answer:

24 cm

Step-by-step explanation:

Given: Picture of the star is made up of 4 unshaded equilateral triangles of equal area and a shaded square.

Area of the shaded region (square) = 9\,\, cm^2

To find: the perimeter of the star

Solution:

Area of the shaded region (square) = 9\,\, cm^2

Area of square = (side)^2

(side)^2=9\\side=3\,\,cm

As each equilateral triangle has side lengths that are the same as the side length of the square,

length of side of the star = 3 cm

Perimeter is the sum of lengths of the sides.

Perimeter of star = sum of 8 sides of the star

= 8 × 3 = 24 cm

4 0
2 years ago
Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random
lesya692 [45]
Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes P_B(A).

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
P(A|B)= \frac{P(A \cap B)}{P(B)}

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is \frac{1}{3}

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}

</span><span>P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

</span><span>Thus P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}

Therefore, P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}


Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
</span><span>
P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}

</span><span>P(D)= \frac{1}{3}</span><span>

Therefore, P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}</span>
3 0
2 years ago
You put $350 per month in an investment plan that pays an APR of 3.5% compounded monthly. How much will you have after
melamori03 [73]

Answer: B.

Step-by-step explanation: TVM Solver Equation:

N = 216 (12 x 18 years)

I% = 3.5

PV = 0

PMT = - $350

FV = 105,106.7593

P / Y = 12 (months)

C / Y = 12

PMT: END

8 0
2 years ago
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