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Illusion [34]
2 years ago
3

Twenty-one people are to be divided into two teams, the Red Team and the Blue Team. There will be 10 people on Red Team and 11 p

eople on Blue Team. In how many ways can this be done?
Mathematics
1 answer:
zvonat [6]2 years ago
4 0

Answer:

352710

Step-by-step explanation:

total number of persons = 21

number of members in red team = 10

number of members in blue team = 11

As we select 10 persons for red team, the rest of the members are in the blue team.

The ways to select 10 persons out of 21

= ^{21}C_{10}=\frac{21!}{10!\times 11!}=352710

Thus, the number of ways to select the 10 members for red team and 11 members for blue team are 352710.

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Which statement is true about the discontinuities of the function f(x)? F (x) = StartFraction x minus 5 Over 3 x squared minus 1
balandron [24]

Question:

Which statement is true about the discontinuities of the function f(x) = \frac{x-5}{3x^2-17x-28}

A)There are holes at x = 7 and .

B)There are asymptotes at x = 7 and .

C)There are asymptotes at x = –7 and .

D)There are holes at (–7, 0) and .

Answer:

B)There are asymptotes at x = 7 and (x = \frac{-4}{3})

Step-by-step explanation:

Given:

f(x) = \frac{x-5}{3x^2-17x-28}

Required:

Find the true statement

f(x) = \frac{x-5}{3x^2-17x-28}

We'll first factorize the denominator.

f(x) = \frac{x-5}{(3x+4)(x-7)}

Make x subject of the formula in (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

x = \frac{-4}{3}

x - 7

x = 7

Now check for the limit when (x = \frac{-4}{3}) and (x = 7)

lim f(x) when   (x = \frac{-4}{3}) = ±∞

lim f(x) when (x=7) = ±∞

Sinve they both make the denominator tend to zero, they are asymptotes

Therefore, there are asymptotes at (x = \frac{-4}{3}) and x=7

Option B is correct

6 0
2 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (-100,0) and (
Gre4nikov [31]

Answer:

\frac {(x)^{2}}{8100}+\frac {(y)^{2}}{1900}=1

Step-by-step explanation:

center of the hyperbola  is  (0,0)  = (h, k)

c = the distance form the center to either focal point  = 100

c^{2} =100^{2}=10000

The differences  from the receiver to the transmitters  =  2a

2a =  180  miles

a   =  180/2=90 miles

a^2 =90^{2}= 8100

b^{2}= c^{2} - a^{2}

b^{2}= 100^{2}-90^{2}=1900

b^{2}=1900

The standard form is

\frac {(x-h)^{2}}{a^{2}}+\frac {(y-k)^{2}}{b^{2}}=1

\frac {(x-0)^{2}}{a^{2}}+\frac {(y-0)^{2}}{b^{2}}=1

\frac {(x)^{2}}{8100}+\frac {(y)^{2}}{1900}=1

3 0
2 years ago
Kendal bought x boxes of cookies to bring to a party. Each box contains 12 cookies. She decides to keep two boxes for herself. S
Georgia [21]

Answer:

Step-by-step explanation:

Total number of boxes of cookies that Kendal bought to bring to the party is x.

Each box contains 12 cookies. This means that total number of cookies in x boxes would be

12 × x = 12x

She decides to keep two boxes for herself. This means that the total number of cookies that she kept for herself would be

12 × 2 = 24 cookies

She brings 60 cookies to the party.

The equation that can be used to find the number of boxes, x, Kendal bought would be

12x = 24 + 60

12x = 84

x = 84/12 = 7 boxes

6 0
2 years ago
A group of 18 people ordered soup and sandwiches for lunch. Each person in the group had either one soup or one sandwich. The sa
sergeinik [125]
X - the number of sandwiches ordered
y - the number of soups ordered

There were 18 people, and each person ordered either one soup or one sandwich.
x+y=18

The sandwiches cost $7.75 each, the soups cost $4.50 each. The total cost was $113.50.
7.75x+4.5y=113.5

Set up a system of equations:
x+y=18 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times (-4.5) \\
7.75x+4.5y=113.5 \\ \\
-4.5x-4.5y=-81 \\
\underline{7.75x+4.5y=113.5} \\
3.25x=32.5 \\
x=\frac{32.5}{3.25} \\
x=10

10 sandwiches were ordered.
The answer is D.
4 0
2 years ago
Edward deposited $6,000 into a savings account 4 years ago. The simple interest rate is 3%. How much money did Edward earn in in
GaryK [48]
Hello IdontKnowHowToMath,

first, converting R percent to r a decimal
r = R/100 = 3%/100 = 0.03 per year.

Solving our equation:
A = 6000(1 + (0.03 × 4)) = 6720
A = $6,720.00

The total amount accrued, principal plus interest, from simple interest on a principal of $6,000.00 at a rate of 3% per year for 4 years is $6,720.00.
6 0
2 years ago
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