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solmaris [256]
2 years ago
15

\begin{aligned} &2x-3y=-5 \\\\ &4x-4y=-4 \end{aligned} ​ 2x−3y=−5 4x−4y=−4 ​ Is (2,3)(2,3)left parenthesis, 2, comma, 3,

right parenthesis a solution of the system
Mathematics
1 answer:
Lilit [14]2 years ago
7 0

Answer:

The correct answer is YES, it is a solution of the system.

Step-by-step explanation:

The system of equations have equations 2x − 3y = −5 and 4x − 4y = −4.

We need to find whether of not (2,3) is a solution to the system of equation.

We multiply the equation 2x − 3y = −5 by 2 and subtract it with the other equation. This gives us,

⇒ 4x - 6y +10 -4x +4y -4 = 0

⇒ 2y = 6

⇒ y = 3.

⇒ x = 2.

Thus ( 2 , 3 ) is the solution.

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Brad says that if a second number is 125% of the first number, then the first number must be 75% of the second number. Is he cor
olga55 [171]

Answer: He is not correct.

Steps:

Let x1 and x2 be the first and second number, respectively.

x_2 = \frac{5}{4}x_1\\\frac{4}{5}x_2 =x_1

In words, if the second is 125%, or 5/4 of the first number (first equation),

then the first is 4/5 of the second, which is 0.8 or 80%.

8 0
2 years ago
Pecans that cost $28.50 per kilogram were mixed with almonds that cost $22.25 per kilogram. How many kilograms of each were used
atroni [7]

Answer:

The pecans used in the mixture =  8 kg

The almonds used in the mixture  =  17 kg

Step-by-step explanation:

The cost of per kg of pecans  = $28.50

The cost of per kg of almonds = $22.25

Now, total weight of mixture  = 25 kg

Let us assume the weight of pecans in the mixture   =   m kg

So, the amount of almonds in the mixture  = Total weight - Weight of Pecans

= (25 - m) kg

Now, cost of m kg pecans  = m x ( cost of 1 kg pecans) = m x ( $ 28.50)

                                              =  28.50 m

cost of (25- m) kg almonds  = (25 -m)  x ( cost of 1 kg almonds)

                                                = (25 - m) x ( $ 22.25)

                                                =  556.25  - 22.25 m

Total cost  of 25 kg of mixture  = 25 x ( $24.25) =  $606.25

Now, Total Cost of (almonds  + Pecans)  = Total cost of mixture

⇒28.50 m + 556.25  - 22.25 m  = $606.25

or,6.25 m =  50

or, m = 50/6.25 =  8

Hence, the pecans used in the mixture = m = 8 kg

And the  almonds used in the mixture  = (25 - m) = 25 - 8 = 17 kg

5 0
2 years ago
1+5+5VE+Y5-5U<br> Help me please
professor190 [17]

Answer:

<h3> I Love You </h3>

Step-by-step explanation:

In this riddle we have to do addition and subtraction to give answer .

<u>Solution::-</u>

<u>l+</u><u> </u><u>5+5</u><u> </u><u>VE+</u><u> </u><u>Y5-5U</u>

<u>l(5+5) VE + Y (5-5) U </u>

<u>I LOVE YOU </u>

8 0
2 years ago
Read 2 more answers
Oishi and Schimmack (2010) report that people who move from home to home frequently as children tend to have lower than average
user100 [1]

Answer:

The well-being for frequent movers is significantly different from well-being in the general population. ( Alternate Hypothesis accepted )

cohen's d = -0.91 , ( Large Effect )

Step-by-step explanation:

Given:-

- A sample of size n = 12

- The population mean u_p = 40

- The sample was taken as:

                     38, 37, 41, 35, 42, 40, 33, 33, 36, 38, 32, 39

Find:-

On the basis of this sample, is well-being for frequent movers significantly different from well-being in the general population? Use a two-tailed test with α = 0.05.

Solution:-

- State the hypothesis for sample mean u_s is same as population mean u_p.

                    Null Hypothesis: u_s = 40

                    Alternate Hypothesis: u_s ≠ 40

- The rejection criteria for the Null hypothesis can be modeled by T-value ( n < 30 ) with significance level α = 0.05.

                    DOF = n - 1 = 12 - 1 = 11

                    Significance level α = 0.05

                    t_α/2 = t_0.025 = +/- 2.201

- For the statistic value we have to compute sample mean u_s given by:

             u_s = Σ xi / n

             u_s = (38 + 37 + 41 + 35 + 42 + 40 + 33 + 33 + 36 + 38 + 32 + 39) / 12

             u_s = 37

- For the statistic value we need population standard deviation S_p given by:

            S_p = S_s / √n

Where, S_s : Sample standard deviation.

            S_s^2 = Σ (xi - u_s)^2 / (n-1)

            =[ 2*(38-37)^2 +  (37-37)^2 + (41-37)^2 + (35-37)^2 + (42-37)^2 + (40-37)^2 + 2*(33-37)^2 + (36-37)^2 + (32-37)^2 + (39-37)^2 ] / ( 11 )

            S_s^2 = [ 2 + 0 + 16 + 4 + 25 + 9 + 32 + 1 + 25 + 4 ] / 11

            S_s^2 = 10.73

            S_s = 3.28

The population standard deviation ( S_p ) is:

            S_p = 3.28 / √12

            S_p = 0.95

- The T-statistics value is computed as follows:

            t = ( u_s - u_p ) / S_p

            t = ( 37 - 40 ) / 0.95 = -3.16

- Compare the T-statistics (t) with rejection criteria (t_α/2).

            -3.16 < -2.201

            t < t_α/2 ...... Reject Null Hypothesis.

- The well-being for frequent movers is significantly different from well-being in the general population. ( Alternate Hypothesis accepted )

- The cohen's d is calculated as follows:

         cohen's d = ( u_s - u_p ) / S_s

         cohen's d = ( 37 - 40 ) / 3.28 = -0.91 ,     ( Large Effect )    

5 0
2 years ago
A rectangular swimming pool measures 14 feet by 30 feet. The pool is surrounded on all four sides by a path that is 3 feet wide.
V125BC [204]

Check the picture below.

since the rectangular pool is a 14x30, the top and bottom part of that rectangle in the picture are just a 3x30 piece and the sides are 3x8, so how many ft² is that?

\bf 2(3\cdot 30)+2(3\cdot 8)\implies 180+48\implies 228~ft^2~\hfill \stackrel{\textit{total cost}}{228\cdot 20\implies \boxed{456}}

3 0
2 years ago
Read 2 more answers
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