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Olegator [25]
2 years ago
10

Pepper jackie used a precision hydrometer to perform an experiment at 2 local restaurants to determine which restaurant uses the

most sugar in their beverages. she randomly tested 15 different types of beverages at each location and performed a conversation to calculate the amount of sugar in grams. the results of the experiment are displayed in the box plot below
Jim's juice joint
65,65,65,66,66,67,69,72,73,75,75,78,80,82,85
The Zest nest
22,25,25,28,30,32,35,35,35,40,42,42,44,45,46

A. ALL of the beverages at The Zest Nest ARE LIKELY to contain 46 grams of sugar or less, but NONE of the beverages at Jim's juice joint ARE LIKELY to contain LESS THAN 46 grams of sugar.

B.HALF of the beverages at The Zest Nest ARE LIKELY to contain 42 grams of sugar or less, but NONE of the beverages at Jim's' juice joint ARE LIKELY contain 42 grams of sugar or less.

C. HALF of the beverages at Jim's juice joint ARE LIKELY to contain 78 grams of sugar or less, but ALL of the beverages at the Zest Nest ARE LIKELY to contain LESS THAN 78 grams of sugar.
Mathematics
2 answers:
klasskru [66]2 years ago
7 0

Answer:

option A

Step-by-step explanation:

From the data, we can conclude that is very probable that all of the beverages at The Zest Nest contain 46 grams of sugar or less and that none of the beverages at Jim's juice joint contain less than 46 grams of sugar. Of course, these conclusions are not 100% sure because they are based on samples.

NISA [10]2 years ago
3 0

Answer:

. ALL of the beverages at The Zest Nest ARE LIKELY to contain 46 grams of sugar or less, but NONE of the beverages at Jim's juice joint ARE LIKELY to contain LESS THAN 46 grams of sugar.




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Find all points of intersection of the given curves. (Assume 0 ≤ θ ≤ 2π and r ≥ 0. Order your answers from smallest to largest θ
DerKrebs [107]

Answer:

∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,

∅8=345°

Step-by-step explanation:

Data

r = 8 sin(2θ), r = 4 and r=4

iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°

according the graph 2, the cut points are:

I quadrant:

0+15° = 15°

90°-15°=75°

II quadrant:

90°+15°=105°

180°-15°=165°

III quadrant:

180°+15°=195°

270°-15°=255°

IV quadrant:

270°+15°=285°

360°-15°=345°

No intersection whit the pole (0)

7 0
2 years ago
Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number
Anastasy [175]
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

6 0
2 years ago
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Segment AB falls on line 2x − 4y = 8. Segment CD falls on line 4x + 2y = 8. What is true about segments AB and CD? They are perp
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Answer:

They are perpendicular because they have slopes that are opposite reciprocals of −2 and one half.

Step-by-step explanation:

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When we use for AB line we see they are perpendicular 2 1/2 x 2 = 5 -4y = 8 shows y to be -2 and the 1/2 line leaves -2 1/2 and x also is 2 1/2.

6 0
1 year ago
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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the​ plate, including t
vredina [299]

You're looking for the extreme values of x^2+3y^2+13x subject to the constraint x^2+y^2\le1.

The target function has partial derivatives (set equal to 0)

\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2

\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0

so there is only one critical point at \left(-\dfrac{13}2,0\right). But this point does not fall in the region x^2+y^2\le1. There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of x^2+y^2\le1 by

x=\cos u

y=\sin u

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t(x,y)=t(\cos u,\sin u)=T(u)

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T(u)=3+13\cos u-2\cos^2u

T(u) has critical points where T'(u)=0:

T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0

(1)\quad\sin u=0\implies u=0,u=\pi

(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4

but |\cos u|\le1 for all u, so this case yields nothing important.

At these critical points, we have temperatures of

T(0)=14

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so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0
2 years ago
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Step-by-step explanation:

Present Value of a Growing Perpuity is calculated using the following formula

PV =D/(r - g)

Where D = Dividend

r = Discount Rate

g = Growth rate

D = $50,000

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r = 7/100

r = 0.07

g = 4%

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g = 0.04

PV = D/(r-g)

Becomes

PV = $50,000/(0.07-0.04)

PV = $50,000/0.03

PV = $1,666,666.67

So the Present Value of the perpuity is $1,666,666.67

4 0
2 years ago
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