Question

Noah and Han are preparing for a jump rope contest. Noah can jump 40 times in 0.5 minutes. Han can jump y times in x minutes, where y= 78x. If they both jump for 2 minutes, who can jump more times? How many more?

Answer 1

Answer: Noah Can jump more in the 2 minutes, Noah can jump 4 more times than Han in the 2 minutes.

Hope this helps!

Answer 2

Answer:

Noah Jumps more than Han in 2 minutes.

Noah jumps 4 more than Han in 2 minutes.

Step-by-step explanation:

Given:

Noah can jump 40 times = 0.5 minutes.

Han can jump y times in x mins.

$y=78x$

We need to find who can jump more in 2 minutes and how much more.

Solution:

First we will find for Noah;

0.5 mins = 40 jumps

2 mins = Number of jumps in 2 mins.

Using Unitary method we get;

Number of jumps in 2 mins = $\frac{40\times2}{0.5}=160$

Hence Noah can jump 160 times in 2 minutes.

Now we will find for Han;

Han can jump y times in x mins.

$y=78x$

$y$ ⇒ Number of Jumps

$x$ ⇒ Number of minutes.

So to find the number of jumps in 2 minutes we will substitute the value of x as 2 in above equation we get;

$y = 78x =78\times2 =156$

Hence Han can jump 156 times in 2 minutes.

Comparing number of jumps of Noah and han we can say that;

Noah Jumps more than Han in 2 minutes.

Also Noah jumps 4 more than Han in 2 minutes.