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insens350 [35]
2 years ago
9

Carolina is mowing lawns for a summer job. For every mowing job, she charges an initial fee plus \$6$6dollar sign, 6 for each ho

ur of work. Her total fee for a 444-hour job, for instance, is \$32$32dollar sign, 32. Let F(t)F(t)F, left parenthesis, t, right parenthesis denote Carolina's fee for a single job FFF (measured in dollars) as a function of the number of hours ttt it took her to complete it. Write the function's formula. F(t)=F(t)=F, left parenthesis, t, right parenthesis, equals
Mathematics
1 answer:
Margarita [4]2 years ago
7 0

For this case, the first thing we must do is define variables.

We have then:

t: number of hours

F (t): total charge

We write the function that models the problem:

F (t) = 6t + b

Where,

b: represents an initial fee.

We must find the value of b.

For this, we use the following data:

Her total fee for a 4-hour job, for instance, is $ 32.

We have then:

32 = 6 (4) + b

From here, we clear the value of b:

32 = 24 + b

32-24 = b

b = 8

Then, the function that models the problem is:

F (t) = 6t + 8

Answer:

the function's formula is:

F (t) = 6t + 8

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Answer:

c

Step-by-step explanation:

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2 years ago
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Just the question about sandy))<br><br>A &amp; B
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A.) 50.45m + 60 = 57.95m

b.) 50.45m + 60 = 57.95m
     60 = 57.95m - 50.45m
     60 = 7.50m
     60 / 7.50 = m
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2 years ago
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
Which of these statements best describes the relation shown in Item 1?
Oksi-84 [34.3K]

Answer:

The relation is 'a function that is one-to-many'.

Step-by-step explanation:

From the table, we can see that element 10 i.e. y=10 in the range, corresponds to two elements i.e. x=-5, and x=5 in the domain.

In other words, the given table represents the many-to-one function as an element of the range y = 10 corresponds to more than one element in the domain.

Therefore, the relation is 'a function that is one-to-many'.

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The domain is
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The range is
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This is because if Haley doesn't use any minutes, the price will stay at $20.
Let me know if you have any questions.
3 0
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