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Angelina_Jolie [31]
2 years ago
4

A ship traveled 120 km with the current, and then turned around and traveled back, spending 5h and 24 min on its trip. Find the

speed of the current if the speed of the ship in still water is 45 km/hour.
Mathematics
1 answer:
Citrus2011 [14]2 years ago
8 0

1.58 km/hr

Step-by-step explanation:

We will assign the current’s speed as <em>x</em> km/hr;

Remember; <em>distance / speed = time</em>

Therefore;

120 / 45 + x + 120 / 45 – x = 5.4

120 (45 – x ) + 120 (45 + x) = 5.4 (45 + x)(45 - x)

5400 – 120x + 5400 + 120x = (243 + 5.4x)(45 - x)

5400 – 120x + 5400 + 120x = 243 (45 - x) + 5.4 (45 - x)

10800 = 10935 – 243x + 243 – 5.4x

10800 – 10935 - 243 = - 234x – 5.4x

-378 = -239.4 x

x = 1.58 km/hr

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The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

5 0
2 years ago
Maria sets a goal of jogging 17.5miles this week. She plans on running 2.75 miles each day for 7 days . If she follows her plan
vovangra [49]
Yes, he will get 19.25 miles.
8 0
2 years ago
Read 2 more answers
Raleigh went to a gaming arcade for his birthday. His parents gave him $55 to spend. He purchased $14.25 in food and drinks, and
xenn [34]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Total amount to spend = $55

Amount of food and drinks purchased = $14.25

Amount put on gaming card = $(55 - 14.25) = $40.75

Cost per game = $1.25

Number of games (g) he can play

Number of games g:

Amount put on gaming card / cost per game

= $40.75 / $1.25

= 32.6 games

g ≤ 32

6 0
2 years ago
In a (blank),one ratio compares a part to a whole
Verdich [7]

Answer:

In a part-to-whole ratio, one ratio compares a part to a whole.

3 0
2 years ago
A bakery sells rolls in units of a dozen. The demand X (in 1000 units) for rolls has a gamma distribution with parameters α = 3,
bearhunter [10]

Answer:

The value  is  E(X) =  \$ 1.7067

Step-by-step explanation:

From the question we are told that

   The  parameters  are  α = 3, θ = 0.5

    The cost of making a unit on the first day  is  c = $2

    The selling price of a  unit on the first day is  s = $5

    The selling price of a leftover unit on the second day is  v  = $ 1

Generally the profit of a unit on the first day is

        p_1 = 5 - 2

           p_1 = \$3

The profit of a unit on the second day is

       p_2 = 1 - 2

=>     p_2 = - \$1

Generally the probability of making profit greater than $ 1 is mathematically represented as

    P(X >  1 ) = Gamma (X ,\alpha , \theta)

=>   P(X >  1 ) = Gamma (1 ,3 , 0.5)

Now from the gamma distribution table  we have that

    P(X >  1 ) =  0.67668

Generally the probability of making profit less than or  equal to  $ 1 is mathematically represented as

       P(X \le  1 ) = 1 - P(X >  1 )

=>     P(X \le  1 ) = 1 - 0.67668

=>     P(X \le  1 ) = 0.32332    

So  the probability of making  $3  is    P(X >  1 ) =  0.67668

and  the probability of making  -$1  is   P(X \le  1 ) = 0.32332  

Generally the value of profit per day is mathematically represented as

      E(X) =  3 *  P(X >  1 )   +   (-1  *  P(X \le 1 ) )

=>     E(X) =  3 * 0.67668   +   (-1  *  0.32332 )

=>     E(X) =  \$ 1.7067

4 0
2 years ago
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