Answer:
<h2>
Offspring are; smooth yellow (SsYy), Smooth green (Ssyy), wrinkled yellow (ssYy) and wrinkled green (ssyy).</h2><h2>
So frequencies of the phenotypes in the offspring of this cross are 25% each.</h2>
Explanation:
Given;
Here the parents are; an F1 hybrid smooth yellow and recessive wrinkled green;
Smooth yellow is an F1 hybrid,
lets assume smooth yellow as; SsYy
S= smooth; S is dominant over s,
Y= yellow; Y is dominant over y.
so wrinkled green is ssyy;
so offspring will be
gametes of SsYy are; SY, Sy, sY and sy
gamets of ssyy = sy type only
so offspring will be;
genotype ; SsYy, Ssyy, ssYy, ssyy,
phenotype; smooth yellow (SsYy), Smooth green (Ssyy), wrinkled yellow (ssYy) and wrinkled green (ssyy).
So frequencies of the phenotypes in the offspring of this cross are 25% each.
