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Andreyy89
2 years ago
3

The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earne

d by selling x cups of lemonade is represented by the function R(x) = 0.50x. What is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?
Mathematics
2 answers:
navik [9.2K]2 years ago
8 0
For the answer to the question above,
revenue to exceed cost: R(x) > C(x)
0.50x > 10 + 0.20x
0.50x - 0.20x > 10
0.30x > 10
x > 10/0.30
x > 33.333

Therefore the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost is 34.
I hope this helps
tresset_1 [31]2 years ago
6 0
Hello there.

<span>The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earned by selling x cups of lemonade is represented by the function R(x) = 0.50x. What is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?
</span>
Answer 34
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