Populations have a genetic variation among individuals and that is important to the populations ability to survive in different situations that have an affect on the natural selection. There are different factors which can increase or decrease the genetic diversity, and influencing natural selection. These factors can include an environmental factor, one of the major factors, which can cause changes in the genetic variation of a population and influence the natural selection. A famous and important example of the environmental factors affecting natural selection was made during the industrial revolution when many more gray moths made up the moth population. This was so that they could blend in with the soot from factories to avoid predators.
Answer:
The compound is dissolved in water
Explanation:
"aq." is the abbreviation for "aqueous" ( watery).
In chemical equations the symbol (aq) means that the substance is dissolved in water.
Answer:
Explanation:
NADH and FADH2 are both electron carriers of the electron transport chain. NADH gives up its electrons starting from Complex I, which has a higher energy level compared to other complexes. Energy is given off to pump protons across the membrane by the time electrons are transferred to ComplexIII. More electrons are pumped across the membrane as electrons move to Complex IV. Because NADH commenced giving up its electrons from Complex I (higher energy level complex), more protons are pumped across the membrane gradient, which enables ATP synthase with more power to produce 3ATP molecules per NADH molecule.
On the other hand, 2 molecules of ATP are generated by FADH2 because it starts by giving up its electrons to ComplexII. It missed a chance to pump protons across the membrane when it passed Complex I. By the time the electrons reach Complex IV, less protons have been pumped. The lesser the protons to power ATP synthase, the lesser the ATP molecules produced.
I assume that in this item, we are asked to solve for the force exerted during the heartbeat. Force is the product of the mass and acceleration. To solve for the acceleration in this item, we divide the velocity by time.
a = 1 m/s / 0.2 s = 5 m/s²
Then, we multiply this by the mass (in kg)
F = (80 g / 1000 g/kg) x (5 m/s²)
= 0.4 kg m/s² = 0.4 J
Therefore, every hearbeat will take 0.4 J of force.
