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Bogdan [553]
2 years ago
12

Alejandro surveyed his classmates to determine who has ever gone surfing and who has ever gone snowboarding. Let A be the event

that the person has gone surfing, and let B be the event that the person has gone snowboarding. Which statement is true about whether A and B are independent events? A and B are independent events because P(A∣B) = P(A) = 0.16. A and B are independent events because P(A∣B) = P(A) = 0.75. A and B are not independent events because P(A∣B) = 0.16 and P(A) = 0.75. A and B are not independent events because P(A∣B) = 0.75 and P(A) = 0.16.
Mathematics
2 answers:
denis-greek [22]2 years ago
8 0

First of all we need to know when does two events become independent:

For the two events to be independent,  that is if condition on one does not effect the probability of other event.

Here, in our case the only option that satisfies the condition for the events to be independent is . Rest are not in accordance with the definition of independent events.

lisov135 [29]2 years ago
8 0

Answer: D

Step-by-step explanation:

No

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Zöe schedules advertising for a radio station. She must fill 12 minutes each hour with 30 second ads and 60 second ads. Zöe sold
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Our system is then
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8 0
2 years ago
In a certain community, eight percent of all adults over age 50 have diabetes. If a health service in this community correctly d
____ [38]

Complete question is;

In a certain community, 8% of all people above 50 years of age have diabetes. A health service in this community correctly diagnoses 95% of all person with diabetes as having the disease, and incorrectly diagnoses 10% of all person without diabetes as having the disease. Find the probability that a person randomly selected from among all people of age above 50 and diagnosed by the health service as having diabetes actually has the disease.

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P(has diabetes | positive) = 0.442

Step-by-step explanation:

Probability of having diabetes and being positive is;

P(positive & has diabetes) = P(has diabetes) × P(positive | has diabetes)

We are told 8% or 0.08 have diabetes and there's a correct diagnosis of 95% of all the persons with diabetes having the disease.

Thus;

P(positive & has diabetes) = 0.08 × 0.95 = 0.076

P(negative & has diabetes) = P(has diabetes) × (1 –P(positive | has diabetes)) = 0.08 × (1 - 0.95)

P(negative & has diabetes) = 0.004

P(positive & no diabetes) = P(no diabetes) × P(positive | no diabetes)

We are told that there is an incorrect diagnoses of 10% of all persons without diabetes as having the disease

Thus;

P(positive & no diabetes) = 0.92 × 0.1 = 0.092

P(negative &no diabetes) =P(no diabetes) × (1 –P(positive | no diabetes)) = 0.92 × (1 - 0.1)

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Probability that a person selected having diabetes actually has the disease is;

P(has diabetes | positive) =P(positive & has diabetes) / P(positive)

P(positive) = 0.08 + P(positive & no diabetes)

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P(has diabetes | positive) = 0.076/0.172 = 0.442

8 0
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Answer:

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Therefore, the population of interest for my study here is the monthly rents recorded from the sample of one bedroom apartments.

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