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dybincka [34]
2 years ago
15

Assume the blood pressures of 10 people were measured before and after sleeping for the night. What is the corresponding critica

l t-value for a one-tailed, paired-samples t test with an alpha level of 0.05 (5%)?
Please report your answer as an absolute value and include three decimal places.
Mathematics
1 answer:
NeX [460]2 years ago
5 0

Answer:

For the critical value we need to calculate the degrees of freedom given by:

df = n-1= 10-1=9

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

|t_{crit}| =1.833

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value with right arm , y = test value with left arm  

The system of hypothesis for this case are:  

Null hypothesis: \mu_y- \mu_x = 0  

Alternative hypothesis: \mu_y -\mu_x \neq 0  

The first step is calculate the difference d_i=y_i-x_i

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{361}{5}  

The third step would be calculate the standard deviation for the differences, and we got:  

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}  

The 4 step is calculate the statistic given by :  

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}  

For the critical value we need to calculate the degrees of freedom given by:

df = n-1= 10-1=9

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

|t_{crit}| =1.833

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Okay, well we start out with the equation P=66, where P is perimeter. You should create equations using variables to explain each piece of information you are given. Follow the equations below and see if you can understand how to do another one like this. In this problem, l is length and w is width.


P = 66                               The perimeter is equal to 66

l = 3 + w                           The length of one side is 3 more than the width

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a=7, b=24, c=25

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a=11, b=60, c=61

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Answer:

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We have the following expression:

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And the common factors are 1,3

The GCF for the numerical part is 3*1 = 3

2. Find the GCF for the variable

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The common factors are x for this case, so then the GCF for the variable part is x

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