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Sunny_sXe [5.5K]
2 years ago
9

Find the number of ideal integers within the given segment [low,high] inclusive. An ideal number is a positive integer that has

only 3 and 5 as prime divisors. An ideal number can be expressed in the form of 3^x*5^y, where x and y are non-negativeintegers
Computers and Technology
1 answer:
Alex Ar [27]2 years ago
6 0

Answer:

  1. low = 10
  2. high = 50
  3. count = 0
  4. for i in range(low, high + 1):
  5.    if(i % 3 == 0 and i % 5 == 0):
  6.        count += 1
  7. print(count)

Explanation:

The solution code is written in Python.

We can create low and high variables to store the lower bound and upper bound in the range (Line 1-2)

Next create a counter variable, count (Line 3).

Use a for loop to traverse through the number between lower bound and upper bound and check if the current number-i is divisible by 3 and by 5, increment the count by one.

After the loop, print the count and we can get the number of ideal integers within the range (Line 8).

You might be interested in
Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco
harina [27]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

//executes when condition1 evaluates to true

 if(condition2) {

//executes when condition1  and condition2 evaluate to true

 }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of one of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40){

  if (busArrived=="yes")   {

      if (!sick)       {

          if (homework=="done")           {

              printf("Go to school.");

          }

      }     

  }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Go to school."; }

6 0
2 years ago
You want to register the domain name ABCcompany.org, but the registration service is not allowing you to do that. What's the mos
Andreyy89

Options :

The domain name is registered to someone else.

Domain names must end in ".com".

You are not the legal owner of ABC Company.

Domain names must be all in lowercase.

Answer:

The domain name is registered to someone else.

Explanation: In the scenario above, ABCcompany.org represents the domain name of a particular person or establishment which provides access to the website of the owner. The domain name given to an individual or website must be distinct, that is no two different organizations or persons can use exactly the same domain name. Domain names can end with :. com, org, ng and various other and they aren't case sensitive. Therefore, the inability to register the domain name abive will likely stem from the fact that the domain name has is already registered to someone else.

6 0
2 years ago
Using the college registration example from section 6.7.3 as a starting point, do the following:
Arada [10]

Answer:

Explanation:

NCLUDE Irvine32.inc

TRUE = 1

FALSE = 0

.data

gradeAverage WORD ?

credits WORD ?

oKToRegister BYTE ?

str1 BYTE "Error: Credits must be between 1 and 30" , 0dh,0ah,0

main PROC

call CheckRegs

exit

main ENDP

CheckRegs PROC

push edx

mov OkToRegister,FALSE

; Check credits for valid range 1-30

cmp credits,1 ; credits < 1?

jb E1

cmp credits,30 ; credits > 30?

ja E1

jmp L1 ; credits are ok

; Display error message: credits out of range

E1:

mov edx,OFFSET str1

call WriteString

jmp L4

L1:

cmp gradeAverage,350 ; if gradeAverage > 350

jna L2

mov OkToRegister,TRUE ; OkToRegister = TRUE

jmp L4

L2:

cmp gradeAverage,250 ; elseif gradeAverage > 250

jna L3

cmp credits,16 ; && credits <= 16

jnbe L3

mov OkToRegister,TRUE ; OKToRegister = TRUE

jmp L4

L3:

cmp credits,12 ; elseif credits <= 12

ja L4

mov OkToRegister,TRUE ; OKToRegister = TRUE

L4:

pop edx ; endif

ret

CheckRegs ENDP

END main

8 0
2 years ago
Which of the following is considered technology?
nevsk [136]
A. computer
computer because computer is technology and pencil is not and spoon.
8 0
2 years ago
A summer camp offers a morning session and an afternoon session.
defon

Answer:

(A) IF (IsFound

(afternoonList, child))

{

APPEND (lunchList, child)

}

Hope this helps!

5 0
2 years ago
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