Question

One of the factors of g2 − 28g + 196 is a. g-7 b. g-14 c. g+14 d. g+7

Answer 1

We can use this formula:

$\sf{x^2-2xy+y^2 =(x-y)(x-y)=(x-y)^{2}}$

$g^2 - 28g + 196 \to (g)^2 - 2(14)(g) + (14)^2$

that means:

$x = g, y = 14$

So plugging that into the formula, you get:

$g^2 - 28g + 196= (g-14)(g-14)= (g-14)^2$

Answer 2

$g^{2}-28g+196=g^{2}-14g-14g+196=g(g-14)-14(g-14)= \\ \\ (g-14)(g-14)=(g-14)^{2}$

P.S :>

$(a-b)^{2}=a^{2}-2ab+b^{2}$

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