Answer:
Protein/enzyme synthesis
Explanation:
<em>The process of synthesis of protein in the cell is mainly responsible for the increase in the protein content of the cell.</em>
<em>The process which is also known as the translation process of gene expression takes place at the G1 and G2 phases of the interphase of the cell cycle.</em>
During protein synthesis, mRNA synthesized in the nucleus are transported to the cytoplasm and the genetic codes on the mRNA are translated into their respective amino acids linked together by polypeptide bonds. The protein are then folded in specific ways for specific enzymes.
Answer: did you figure it out?
Explanation:
Answer:
A
Explanation:
The correct answer would be that <u>the cell was submerged in a hypertonic solution.</u>
<em>A hypertonic solution is a solution with a higher concentration of solutes than that of the cytosol of a cell suspended in it. When a cell is suspended in a hypertonic solution, water moves osmotically from the cytosol to the hypertonic solution. This causes the cytoplasm to collapse and the cell becomes flaccid. </em>
The correct option is A.
Answer:
1. heterozygous yellow and star
2. 37
3. 1/8
4. 168
5. 1/4
Explanation:
Given ,
In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch
yySS x YYss
It is taken as - Y (yellow) is dominant over y (black)
and S (star) is dominant over s (starless)
1. F1 Generation
Genotype of parents yySS X YYss
gametes - yS, yS, Ys, Ys
All 16 offspring will have genotype YySs
phenotype would be heterozygous yellow and star
2. F2 generation cross
YySs X YySs
YS Ys yS ys
YS YYSS YYSs YySS YySy
Ys YYSs YYss YySs Yyss
yS YySS YySs yySS yySs
ys YySs Yyss yySs yyss
Genotype of offspring are –
YYSS – 1
YYSs – 2
YySS – 2
YySs – 4
YYss- 1
Yyss- 2
yySS – 1
yySs- 1
yyss- 1
2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches
So out of 300, 37 are black star bellied sneetches
3. Only 2 out of 16 are true breeding. i.e 1/8
4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches
5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding
the answer of your question is cytoplasm