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2 years ago

What is the area of the base of the cone below?

Mathematics

1 answer:

frutty [35]2 years ago

8 0

<u>Given</u>:

Given that the height of the cone is 12 ft.

The volume of the cone is 90 ft³

We need to determine the area of the base of the cone.

The area of the base of the cone can be determined using the formula,

$V=\frac{1}{3} \pi r^2 h$

where the base area is $A=\pi r^2$

Substituting the value of A in the above formula, we get,

$V=\frac{1}{3}A h$

Substituting V = 90 and h = 12, we get;

$90=\frac{1}{3}A (12)$

$90=4A$

Dividing both sides by 4, we get;

$22.5 =A$

Thus, the area of the base of the cone is 22.5 square feet.

Hence, Option c is the correct answer.

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2 years ago

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2 years ago

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xxMikexx [17]

Answer:

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Step-by-step explanation:

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We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

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2 years ago

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Answer:

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2 years ago

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