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lozanna [386]
2 years ago
4

One of the concepts your friends are trying out are gourmet Burgers. After having a large group of potential student customers s

ample their burgers and collecting information on how much each one was willing to pay for the meal, the summary statistics were computed as follows: n
n=85 x-bar=$8.32 s=$3.11

MAKE A 95% Confidence Interval for μ
CONDUCT a Significance Test for μ
Mathematics
1 answer:
Sholpan [36]2 years ago
4 0

Answer: Confidence interval : (7.659.8.981)

Step-by-step explanation:

Since we have given that

n = 85

\bar{x}=8.32

s = 3.11

At 95% confidence, z = 1.96

Margin of error would be :

ME=z\dfrac{s}{\sqrt{n}}\\\\ME=1.96\times \dfrac{3.11}{\sqrt{85}}\\\\ME=0.661

So, confidence interval for μ would be:

\bar{x}\pm ME\\\\=8.32\pm 0.661\\\\=(8.32-0.661,8.32+0.661)\\\\=(7.659.8.981)

Significance test for μ :

H_0:\bar{x}=8.32\\\\H_1:\bar{x}\neq 8.32

Hence, confidence interval would be (7.659.8.981)

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