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kap26 [50]
2 years ago
14

Dr. Park is interested in how the functioning of the brain changes with age and how this, in turn, affects older individuals’ me

mory abilities. She randomly selects 11 older and 16 younger adults to study pictures of landscapes presented for 5 seconds each. After a 10-minute rest period, both groups perform a visual recognition test. They view a series of pictures and categorize each as either "old" (part of the set they studied) or "new" pictures. While this test is occurring, researchers use fMRI to measure the participants’ brain activity. Dr. Park and her team notice that the older adults all produced similar amounts of activity during the task. The younger adults, on the other hand, showed much more diversity of brain activity. Some younger study participants had a large amount of activity, while others had much less. Would it be valid for Dr. Park to use the independent-measures t test to test whether the brain activity of younger adults is different from that of older adults during a visual recognition task?
a. Yes, because none of the assumptions of the independent-measures t test are violated.
b. Yes, because the independent-measures t test is a robust test. No, because the two groups studied are not independent.
c. No, because the two populations from which the samples are selected do not appear to have equal variances.
Mathematics
2 answers:
a_sh-v [17]2 years ago
8 0

Answer:

Option C.  No, because the two populations from which the samples are selected do not appear to have equal variances.

Step-by-step explanation:

The variance measures how far a set of (random) numbers are spread out from their average value.

The fact that the younger adults show diversity in their brain activity while the older adults produce similar activities show that there are no equal variances in the two populations from which the samples are selected.

Therefore it would not be valid for Dr. Park to use the independent-measures t-test to test whether the brain activity of younger adults is different from that of older adults during a visual recognition task

AnnZ [28]2 years ago
5 0

Answer:

No, because the two populations from which the samples are selected do not appear to have equal variances.

Step-by-step explanation:

We know that in the given study the two groups studied are older and younger people. The samples are randomly selected and are independent of each other. The t-test is a robust test if the assumptions are followed. In the given study, we are given that the older adults produced a similar response, while the younger adults produced more of diverse brain activity. Therefore, the variance of younger adults would not be equal to the variance of older adults. Since one of the assumptions of the t-test is that the population of the two groups have same variance and here this assumption appears to be violated. Hence the correct option is:  No, because the two populations from which the samples are selected do not appear to have equal variances.

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A marketing survey of Anytown found that the ratio of trucks to sedans to motorcycles was 3:7:2, respectively. Given that there
gayaneshka [121]

Answer:3600 motorcycles

Step-by-step explanation:

The total ratio is first obtained then the total number of automobiles is obtained from the number of sedans given. From this, the number of motorcycles can be obtained using the ratio of motorcycle multiplied by the total number of automobiles.

3 0
2 years ago
At the beginning of year 1, paolo invests $500
suter [353]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$500\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annuall, thus once}
\end{array}\to &1\\
t=years\to &t
\end{cases}
\\\\\\
A=500\left(1+\frac{0.04}{1}\right)^{1\cdot t}\implies A=500(1+0.04)^t
\\\\\\
\textit{after 5 years }t=5\qquad A=500(1.04)^5

the example on your picture uses A(n) and n = years, but is pretty much the same, in this case is t = years.
3 0
2 years ago
Read 2 more answers
The list price on slacks is $22, and the list price on jumpers is $37. If Petit’s Clothing Store orders 30 pairs of slacks and 4
hichkok12 [17]

Answer:

The trade discount is

$235.4

Step-by-step explanation:

Given data

Slacks= $22

Jumpers= $37

Number of orders for Slacks= 30

Number of orders for Jumpers= 40

Total cost

22*30=$660

37*40=$1480

=$2140

11% discount can be computed as

=11/100*2140

=$235.4

7 0
1 year ago
A store sells different kinds of candy at $1, $1.50, $2, and $3 per kilogram. How many kilograms of each kind of candy does $3 b
Afina-wow [57]

Answer and Explanation:

Given : A store sells different kinds of candy at $1, $1.50, $2, and $3 per kilogram.  

To find : How many kilograms of each kind of candy does $3 buy?

Explain why the price of 1 kg and the amount of candy that $3 can buy are inversely proportional quantities?

Solution :

The total amount spent on buying candies is $3.

A store sells different kinds of candy at $1, $1.50, $2, and $3 per kilogram.

When the cost of candies is $1 per kg.

Amount of candies bought is \frac{3}{1}=3\ kg

When the cost of candies is $1.50 per kg.

Amount of candies bought is \frac{3}{1.50}=2\ kg

When the cost of candies is $2 per kg.

Amount of candies bought is \frac{3}{2}=1.5\ kg

When the cost of candies is $3 per kg.

Amount of candies bought is \frac{3}{3}=1\ kg

\text{Unit price of candies}\propto\frac{1}{\text{Amount of candies}}

The amount spent on candies is constant.

\text{Constant of variation}=\frac{\text{Difference in unit price of candies}}{\text{Difference in the amount of candies}}

The difference in the unit price of candies = 3-2=1

The difference in the amount of candies = 1-1.5=-0.5

\text{Constant of variation}=\frac{1}{-0.5}=-2

The negative sign indicates the inverse proportionality.  

6 0
2 years ago
Help. me. pls.
jenyasd209 [6]

it is D because my teacher and I did a  sample test and these were one of the questions plus i've seen people with the same answer for this question. take my word for it

4 0
2 years ago
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