HELP PLS and quick find the volume
1 answer:
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Answer:
The number of outfits she purchase with the left money = 3
Step-by-step explanation:
The exact question is as follows :
Given - Nevaeh has $560 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax. She buys a new bicycle for $383.32. She buys 4 bicycle reflectors for $9.09 each and a pair of bike gloves for $21.07. She plans to spend some or all of the money she has left to buy new biking outfits for $39.75 each.
To find - Write and solve an inequality which can be used to determine x where x, the number of outfits Nevaeh can purchase while staying within her budget.
Proof -
Given that,
Total money Nevaeh have = $ 560
She spent money on bicycle = $ 383.32
She spend money on 1 reflector = $ 9.09
As she buy 4 bicycle reflector, So
Total money spent on bicycle reflector = $ 4×9.09 = $ 36.36
She spend money on a pair of bike gloves = $ 21.07
So,
Total money she spend on the items = $ 383.32 + 36.36 + 21.07
= $ 440.75
⇒Total money she spend on the items = $ 440.75
So,
Total money Left = $ 560 - $ 440.75 = $ 119.25
Now,
She plans to spend some or all of the money she has left to buy new biking outfits for $ 39.75 each.
Let us assume ,
The number of outfits she purchase with the left money = x
AS,
each outfit cost = $ 39.75
So, x outfits cost = $ 39.75 x
Now,
$ 39.75 x = $ 119.25 (because total money left = $ 119.25)
⇒ x = = 3
∴ we get
The number of outfits she purchase with the left money = x = 3
<h3>Answer:</h3>
- using y = x, the error is about 0.1812
- using y = (x -π/4 +1)/√2, the error is about 0.02620
The actual value of sin(π/3) is (√3)/2 ≈ 0.86602540.
If the sine function is approximated by y=x (no error at x = 0), then the error at x=π/3 is ...
... x -sin(x) @ x=π/3
... π/3 -(√3)/2 ≈ 0.18117215 ≈ 0.1812
You know right away this is a bad approximation, because the approximate value is π/3 ≈ 1.04719755, a value greater than 1. The range of the sine function is [-1, 1] so there will be no values greater than 1.
___
If the sine function is approximated by y=(x+1-π/4)/√2 (no error at x=π/4), then the error at x=π/3 is ...
... (x+1-π/4)/√2 -sin(x) @ x=π/3
... (π/12 +1)/√2 -(√3)/2 ≈ 0.026201500 ≈ 0.02620