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Yuliya22 [10]
2 years ago
6

A zealous geologist is sponsoring a contest in which entrants have to guess the age of a shiny rock. He offers these clues: the

age of the rock is formed from the six digits 2, 2, 2, 3, 7, and 9, and the rock's age begins with an odd digit. How many possibilities are there for the rock's age
Mathematics
1 answer:
nataly862011 [7]2 years ago
3 0

Answer:

The total number of possibilities are 60.

Step-by-step explanation:

Given:

There are 6 digits and 3,7,9 are odd ones.

To Find:

How many possibilities are there for the rock's age

Solution:

Here condition is that number should start with odd digit

so there 3 number only as odd(3,7,9)

So it leaves 3 repeating  numbers i.e.2

So permutation of 5 numbers with 3 odd numbers

So possible arrangement will be

nPr

n=5 ,r=3

So 5P3=5!/3!

And finally for all possibilities as

=3*(5!/3!)

=3*(20)

=60

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If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
Gala2k [10]

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

mHMK=\frac{1}{2}(mJL+mHLK)

On putting the values in the above formula, we get

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

On applying cross-multiplication, we get

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

On subtracting "18x" from both sides, we get

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

On adding "2" both sides, we get

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

So that mHLK = (204)°

4 0
2 years ago
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