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2 years ago

Do autotrophs need to perform cellular respiration?

1 answer:

4 0

Many autotrophs make food through the process of photosynthesis, in which light energy from the sun is changed to chemical energy that is stored in glucose. All organisms use cellular respiration to break down glucose, release its energy, and make ATP. Autotrophs are also called producers. They produce food not only for themselves but for all other living things as well (which are known as consumers). This is why autotrophs form the basis of food chains.
Yes, autotrophs need to perform cellular respiration.

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Suppose that of a cohort of 150 mice in a mouse colony born in February, 125 are still at the end of March and 115 are still ali

kogti [31]

Answer: Survival rate up to start of April = 76.67%

Explanation: size of colony = 150mice.

Size of colony in February =125mice.

Size of colony in march = 115 mice.

1. Survivorship rate in February

= Size of colony / size in February *100.

= 122 / 150 * 100

= 83.33% to the nearest hundredth

2. Survivorship rate in march

= Size of colony / size in march *100.

= 115/150 * 100

= 76.67% to the nearest hundredth.

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2 years ago

There are three major types of cells in the lymphoid tissues of the body. One category, the ____________, contains immunocompete

KonstantinChe [14]

Answer:

See the picture attached

Explanation:

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2 years ago

Whole, intact shell eggs must be stored at a temperature of _______ to be kept safe?

Alexxx [7]

The answer is Air temperature of 45 degrees F or lower. I<span>t is very important to refrigerate them at a temperature of 45 °F or below. Keep the eggs in their carton and place them in the coldest part of the refrigerator, not in the door. Storing eggs in the refrigerator door could lead to temperature fluctuations that can lead to bacteria growth.</span>

7 0

2 years ago

Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque

Dmitry [639]

Answer:

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

J and K are autosomal genes

J and K are separated by 60 M.U.

60 M.U. means that there is 60% of recombination.

Cross) J K / j k x j k / j k

Gametes) JK Parental jk, jk, jk, jk

jk Parental

Jk Recombinant

jK Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

30% Jk + 30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

20% JK + 20% jk

Punnet Square) JK jk Jk jK

jk JK/jk jk/jk Jk/jk jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

3 0

2 years ago

Saturated fatty acids are degraded by the stepwise reactions of beta-oxidation, producing acetyl-CoA. Under aerobic conditions,

Tanya [424]

Answer:

4 ATP molecules

Explanation:

Normally, about 11 ATP molecules are generated as the result of Beta-Oxidation of saturated fatty acid in Kreb's Cycle. But the total removal of acetyl-CoA under certain aerobic condition decreases the overall yield and approximately 4 ATP molecules comes out from each removal of acetyl-CoA.

7 0

1 year ago