Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
36c^3m^3x^2
Step-by-step explanation:
- you first multiply 3 cm by 4 cm by 3 cm to get 36 cm.
- its mass in air and its effective mass when submerged in water (density = 1 gram per cubic centimeter).
- 1.0 g/cm3
- then you get the answer 36c^3m^3x^2
Answer:
3 1/3 cups of flour
Step-by-step explanation:
20/4 = 5
20 servings is 5 times 4 servings, so you need 5 times the amount of ingredients.
5 * 2/3 = 10/3 = 3 1/3
Answer: 3 1/3 cups of flour
In general this property looks like
a*1 = a.
This is identity property of multiplication, or multiplicative identity property.
