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1 year ago

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Amber is trying to solve 3x^2-4x=0 using a graphical method. She therefore starts by drawing the graph of y=3x^2 on a grid she n

ow intends to complete her method by drawing a straight line graph in the same grid. complete Ambrrs method to solve 3x^2-4x=0

2 answers:

Delvig [45]1 year ago

6 0

Draw a graph of y=4x, and the x-coordinates of the points of intersection, if I’m not mistaken, are the answers.

AVprozaik [17]1 year ago

5 0

You can rewrite the equation as

$3x^2-4x=0 \iff 3x^2=4x$

So, you draw the graph of $y=3x^2$ (the parabola), and then the graph of $y=4x$ (the line), and see where they intersect.

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At summer camp the ratio of boys to girls was 7:2 If there were 21 boys how many girls were there?

Alenkinab [10]

$Ratio:\\7:2\\\\
7x-number\ of\ boys\\2x-number\ of\ boys\\\\
7x=21\ \ \ |:7\\
x=3\\\\
2x=2*3=6\\
Number\ of\ girls\ is\ equal\ to\ 6.$

3 0

1 year ago

Subtract 7x + 4y − 2z from 4x + 2y.

sukhopar [10]

Answer:

-3x-6y-2z

Step-by-step explanation:

(4x - 2y)-(7x+4y-2z) = 4x-2y-7x-4y-2z = -3x-6y-2z

I hope that's the answer.

7 0

1 year ago

The Helheim glacier in Greenland enters the ocean in a 6.3 kilometer wide fjord. The terminus of the glacier retreated 7.5 kilom

vladimir1956 [14]

Answer:

7.56 km²

Step-by-step explanation:

Given data:

Width of the fjord, w = 6.3 km

Retreated terminus of the glacier between may 2001 and June 2005, d = 7.5 km

thus, the length lost , y = 7.5 - 6.3 = 1.2 km

now, the area is given as:

A = Length × width

on substituting the values, we get

A = 1.2 × 6.3

or

A = 7.56 km²

Hence, the surface area lost by the glacier in the fjord is 7.56 km²

7 0

1 year ago

If r=[x,y,z] and r0=[x0,y0,z0], describe the set of all points (x,y,z) such that Ir-r0I =1.

sdas [7]

Answer:

The points (x,y,z) that respond to Ir-r0I =1, are all that describes the form $(x-x_0)^2+(y-y_0)^2+(z-z_0)^2=1$ with:

-1+x₀<x<1+x₀

-1+y₀<y<1+y₀

-1+z₀<z<1+z₀

Step-by-step explanation:

All points required in this problem came from applying the definition of modulus of a vector:

Ir-r0I =1.

$|(x,y,z)-(x_{0},y_{0},z_{0})|=|(x-x_{0},y-y_{0},z-z_{0})|=\sqrt{(x-x_{0})^2+(y-y_{0})^2+(z-z_{0})^2}=1\\(x-x_{0})^2+(y-y_{0})^2+(z-z_{0})^2=1^2=1$

5 0

1 year ago

If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.

fenix001 [56]

Given:

$h:k=2:5,x:y=3:4,2h+x:k+2y=1:2$

To find:

$h-x:k-y$

Solution:

We have, $h:k=2:5$ and $x:y=3:4$ .

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

$2h+x:k+2y=1:2$

It can be written as

$\dfrac{2h+x}{k+2y}=\dfrac{1}{2}$

$\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}$

$\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}$

$2(4a+3b)=1(5a+8b)$

On further simplification, we get

$8a+6b=5a+8b$

$8a-5a=8b-6b$

$3a=2b$

$a=\dfrac{2b}{3}$

Now,

$h-x:k-y=\dfrac{h-x}{k-y}$

$h-x:k-y=\dfrac{2-3b}{5a-4b}$

$h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}$

$h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}$

On further simplification, we get

$h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}$

$h-x:k-y=\dfrac{-5b}{-2b}$

$h-x:k-y=\dfrac{5}{2}$

$h-x:k-y=5:2$

Therefore, the ratio $h-x:k-y$ is $5:2$ .

8 0

1 year ago