<span>8 is a common factor for all coeficients so we factor it out first: 8(2x^2 + x + 4). Now we have to check can we factor the quadratic equasion in the brackets to linear factors. To do that we need to check is the discriminant D=b^2 - 4ac > 0 where a=2, b=1 and c=4. When we insert our numbers, we get: D= -31. We see that D < 0 so 8(2x^2 + x + 4) is the completely factored form.</span>
60x4=240 tensx4=40 tens=10
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Gross pay = $2,759.00
Total deductions = 7.65%+12%+7% = 26.65% = 0.2665
By thumb rule, rent and other fixed expenses ≤ 28% of Monthly gross salary
Therefore,
Allowed housing and fixed expenses = 0.28*2,759 = $772.52
Then, a. is the correct answer.
