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tankabanditka [31]
2 years ago
5

Both sets of values have an average of 13. Is Set A's standard deviation smaller, larger, or about the same as Set B's? (Note: T

his question can be answered by knowing the concept of standard deviation, without actually computing the standard deviation).
Set A: 1 2 3 23 24 25

Set B: 8 10 12 14 16 18
Mathematics
1 answer:
Softa [21]2 years ago
5 0

Answer:

  Set A's standard deviation is larger than Set B's

Step-by-step explanation:

Standard deviation is a measure of variation. One way to judge the value of standard deviation is by looking at the range of the data. In general, a dataset with a smaller range will have a smaller standard deviation.

The range of data Set A is 25-1 = 24.

The range of data Set B is 18-8 = 10.

Set A's range is larger, so we expect its standard deviation to be larger.

__

The standard deviation is the root of the mean of the squares of the differences from the mean. In Set A, the differences are ±12, ±11, ±10. In Set B, the differences are ±5, ±3, ±1. We don't actually need to compute the RMS difference to see that it is larger for Set A.

Set A's standard deviation is larger than Set B's.

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4/5

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5 0
2 years ago
The mechanics at Giuseppe’s Auto House specialize in changing fuel injection units and transmissions. Last week, they changed 5
Lemur [1.5K]

Answer:

The solution is  (2,6)

Step-by-step explanation:

Let

x-----> the number of hours to change a fuel injection unit

y-----> the number of hours to change a transmission

we know that

5x+10y=70 -----> equation A

8x+8y=64 -----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (2,6)

see the attached figure

4 0
2 years ago
Read 2 more answers
The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
2 years ago
A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

                                                                                                            = $10,000

If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

                                                         = (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0
2 years ago
Charlie is watching hot air balloons. Balloon A has risen at a 60° angle. Balloon B has risen at an 82° angle. If the distance f
babymother [125]

Answer:

(B)1005 feet

Step-by-step explanation:

In the attached diagram

\angle y =82^\circ\\\angle x =60^\circ

|AG|=1400 feet

Distance from point C to point G=|CG|

Using Trigonometry in Triangle ACG

\tan 60^\circ=\dfrac{1400}{CG}\\ CG=\dfrac{1400}{\tan 60^\circ}\\\approx 808$ feet

Using Trigonometry in Triangle BCG'

\tan 82^\circ=\dfrac{1400}{CG'}\\ CG'=\dfrac{1400}{\tan 82^\circ}\\\approx 197$ feet

Therefore, the distance from balloon B from balloon A

=CG+CG'

=808+197

=1005 feet

4 0
2 years ago
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