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muminat
2 years ago
11

The dimension of a rectangular pool are 24.5 feet by 13 feet. The depth of the water is 4 feet. Each cubic foot contains 7.48 ga

llons of water. How many gallons of water to the nearest tenth, are needed to fill the pool to 80% capacity
Mathematics
2 answers:
kupik [55]2 years ago
8 0

Answer:

Pool needed to be filled = 7623.62 gallons

Step-by-step explanation:

Length of rectangular pool = 24.5 feet

Width of rectangular pool = 13 feet

Depth of rectangular pool = 4 feet

Now, Volume of the pool = Length × Width × Depth

                                          = 24.5 × 13 × 4

                                          = 1274 cubic feet

Now, 1 cubic feet = 7.48 gallons

⇒ 1274 cubic feet = 7.48 × 1274

                              = 9529.52 gallons

So, Volume of the pool = 9529.52 gallons

Now, the pool is to be filled 80%

So, Pool needed to be filled = 9529.52 × 0.80

                                                 = 7623.62 gallons

pishuonlain [190]2 years ago
6 0
Multiply length by width, and height. Than multiply the volume by 7.48 gal. Than you have the amount of water that can fill the whole pool. Than multiply by 0.8. and subtract it from the original volume. 
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Answer:

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Step-by-step explanation:

To find how much the passenger car holds, we need to first find what 50% of the trucks gas tank holds.

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Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

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Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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In this problem, we have that:

n = 15000, p = 0.09

So

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What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

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Z = 4.25 has a pvalue of 1.

1 - 1 = 0

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