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2 years ago

How do i use autofill to fill the range A9:H11 with the formatting from the range A7:H8

Computers and Technology

1 answer:

myrzilka [38]2 years ago

3 0

Answer:

See the explanation below

Explanation:

An image showing the range of cells is attached.

The task is to use autofill to fill the range of A9:H11 with the formatting from the range of A7:H8;

As shown in the image some cells are already filled. First, we highlight the cells A7:H8 and then we move the cursor to the end of the selected cell (precisely end of H8) over what is called Fill Handle and the cursor then turns into a black plus sign.

Hold down the right mouse button and drag over the wanted range of cells (A9:H11) and release.

A list of options is presented, this options include:

Copy cells, Fill series, Fill formatting only, Fill without formatting and so on.

From the displayed options, we select "Fill formatting only" and the cell (A9:H11) will have the same formatting as the cells (A7:H8).

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Return 1 if ptr points to an element within the specified intArray, 0 otherwise.

Paladinen [302]

Answer:

int withinArray(int * intArray, int size, int * ptr) {

if(ptr == NULL) // if ptr == NULL return 0

return 0;

// if end of intArr is reached

if(size == 0)

return 0; // element not found

else

{

if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

return 1; // return 1

return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

}

Explanation:

Above is the completion of the program.

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2 years ago

#Write a function called is_composite. is_composite should #take as input one integer. It should return True if the #integer is

malfutka [58]

Answer:

// A optimized school method based C++ program to check

// if a number is composite.

#include <bits/stdc++.h>

using namespace std;

bool isComposite(int n)

{

// Corner cases

if (n <= 1) return false;

if (n <= 3) return false;

// This is checked so that we can skip

// middle five numbers in below loop

if (n%2 == 0 || n%3 == 0) return true;

for (int i=5; i*i<=n; i=i+6)

if (n%i == 0 || n%(i+2) == 0)

return true;

return false;

}

// Driver Program to test above function

int main()

{

isComposite(11)? cout << " true\n": cout << " false\n";

isComposite(15)? cout << " true\n": cout << " false\n";

return 0;

}

Explanation:

3 0

2 years ago

Rohan is creating a presentation with at least 50 slides. He wants the slides to use a consistent layout and formatting. Which o

erma4kov [3.2K]

The parts of the presentation that he should design first is Slide master

Slide master is a slide that enables you to do the following:

•Modify your presentation to suit your taste

•It enables you to make a partial or minor change on the slide layout of your presentation

•Slide master help you to create a perfect and special presentation.

•With Slide master you can easily modify your slide text color.

Inconclusion The parts of the presentation that he should design first is Slide master.

Learn more about Slide master here:

brainly.com/question/12600334

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2 years ago

Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times

otez555 [7]

Answer:

The program written in python is as follows

def countchr(phrase, char):

count = 0

for i in range(len(phrase)):

if phrase[i] == char:

count = count + 1

return count

phrase = input("Enter a Phrase: ")

char = input("Enter a character: ")

print("Occurence: ",countchr(phrase,char))

Explanation:

To answer this question, I made use of function

This line defines function countchr

def countchr(phrase, char):

This line initializes count to 0

count = 0

This line iterates through each character of input phrase

for i in range(len(phrase)):

This line checks if current character equals input character

if phrase[i] == char:

The count variable is incremented, if the above condition is true

count = count + 1

The total number of occurrence is returned using this line

return count

The main method starts here; This line prompts user for phrase

phrase = input("Enter a Phrase: ")

This line prompts user for a character

char = input("Enter a character: ")

This line prints the number of occurrence of the input charcater in the input phrase

print("Occurence: ",countchr(phrase,char))

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2 years ago

A __________ error does not prevent the program from running, but causes it to produce incorrect results. a. syntax b. hardware

Lunna [17]

Answer:

1) syntax error

2)task

3)algorithm

4) pseudocode

5)flowchart

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2 years ago