Bill said, “I am half as old as my sister was last year.” If Bill is now 8 years old, how old is Bill’s sister?

Fresh pond has a population of 854 and is increasing by 3 people per year. Strawberry has a population of 427 and is increasing

lawyer [7]

Answer:

Fresh Pond: p(t) = 854 +3t
Strawberry: p(t) = 427·1.10^t

Step-by-step explanation:

(a) The general term of an arithmetic sequence is ...

an = a1 + d(n -1)

If we let the sequence of population numbers be modeled by this, and we use t for the number of years, we want n=1 for t=0, so n = t+1 and we have ...

p(t) = 854 +3(t+1-1)

p(t) = 854 +3t

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(b) The general term of a geometric sequence is ...

an = a1·r^(n-1)

were r is the common ratio. Here, the multiplier from one year to the next is 1+10% = 1.10. Again, n=t+1, so the population equation is ...

p(t) = 427·1.10^(t+1-1)

p(t) = 427·1.10^t

3 0

2 years ago

The combined average weight of an okapi and a llama is 450450450 kilograms. The average weight of 333 llamas is 190190190 kilogr

notsponge [240]

First of all, lets consider that you made a litte mistake and you meant this problem.........

<span>"The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than the average weight of one okapi. On average, how much does an okapi weigh, and how much does a llama weigh?"

This is a system of two equations.

Let it be X the average weight of a LLAMA
And Y the average weight of an OKAPI

X + Y = 450 kg 1)
3X = 190 kg +Y 2)

So, with 1) we have that Y = 450 - X
We subsitute in 2) and we have

3X = 190 + (450 -X).............We solve for X ....==> 4X = 640kg ==> X = 160kg

..We replace X in 1 and get => Y = 450kg -X = 450kg -160kg = 290kg

</span>160kg....... average weight of a LLAMA
290kg........average weight of an OKAPI

3 0

2 years ago

Read 2 more answers

The equations 3 x minus 4 y = negative 2, 4 x minus y = 4, 3 x + 4 y = 2, and 4 x + y = negative 4 are shown on the graph below.

stich3 [128]

Answer:

(–1.4, 1.5)

Step-by-step explanation:

The blue line and the purple line are the lines corresponding to the equations of interest. Their point of intersection is in the 2nd quadrant, so is nearest to ...

(–1.4, 1.5)

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It can be useful to understand that for equations in standard form:

ax +by = c

the x- and y-intercepts are ...

x-intercept: c/a . . . . value of x for y = 0
y-intercept: c/b . . . . value of y for x = 0

__

For the equations of interest, the first has intercepts of ...

x=2/3, y=1/2 . . . . graphed line makes a 1st-quadrant triangle with the axes (blue line)

And the second has intercepts of ...

x=-1, y=-4 . . . . graphed line makes a 3rd-quadrant triangle with the axes (purple line)

Since the purple line has a steeper slope, the point of intersection of the lines will be in the 2nd quadrant. There is only one 2nd-quadrant answer choice: (-1.4, 1.5).