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rosijanka [135]
2 years ago
8

A box contains fifteen billiard balls, numbered 1 through 15. Anna draws a ball, records the number, and then returns it to the

box. Then Vicki draws a ball. Find the probability of rolling an even number than an odd number.
Mathematics
1 answer:
Drupady [299]2 years ago
6 0

The correct end part of the question says;

Find the probability of rolling an even number "then" an odd number

Answer:

Probability of rolling even, then odd = 56/225

Step-by-step explanation:

Now, the numbers are from 1 to 15.

Since we want find probability of even, then odd number, let's list all the even numbers first;

Even numbers from 1 to 15 are;

2, 4, 6, 8, 10, 12, 14

Odd numbers from 1 to 15 are;

1, 3, 5, 7, 9, 11, 13, 15

So, we have 7 even numbers and 8 odd numbers.

Probability of even is = 7/15

Probability of odd is = 8/15

Thus,probability of rolling even, then odd is;

P(even, then odd) = 7/15 x 8/15 = 56/225

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soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of 2\pi and a vertical compression.

Step-by-step explanation:

We are given the parent function as y= \cot x

It is given that, transformations are applied to the parent function in order to obtain the function y=0.5\cot (0.5x) i.e. y=\frac{1}{2}\cot (\frac{x}{2})

That is, we see that,

The parent function y= \cot x is stretched horizontally by the factor of \frac{1}{2} which gives the function y=\cot (\frac{x}{2}).

Further, the function is compressed vertically by the factor of \frac{1}{2} which gives the function y=\frac{1}{2}\cot (\frac{x}{2}).

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period \frac{P}{|b|}.

Since, the period of y= \cot x is \pi, so the period of y=\frac{1}{2}\cot (\frac{x}{2}) is \frac{\pi}{1/2} = 2\pi

Hence, we get option C is correct.

3 0
2 years ago
The height h of the equilateral triangle below is given by y= 5 cot theta where theta = 30 degrees
brilliants [131]
To solve this we can take two different approaches:

1. We can substitute theta by 30° and evaluate our expression using a calculator: 
y=5cot( \alpha )
y=5cot(30)
y=8.7

2. We can use the unitary circle and the fact that cot \alpha = \frac{cos( \alpha }{sin( \alpha )}, so we can rewrite our expression as follows:
y=5cot( \alpha )
y=5 \frac{cos( \alpha )}{sin( \alpha )}
y= \frac{cos(30)}{sin(30)}
From our unitary circle we can check that cos(30)= \frac{ \sqrt{3} }{2} and sin(30)= \frac{1}{2}. 
Lets replace those values in our expression and simplify:
y= \frac{ 5(\frac{ \sqrt{3} }{2})}{ \frac{1}{2} }
y=5 \sqrt{3}
y=8.7

Either way we can conclude that the correct answer is: D)8.7

6 0
2 years ago
A bug is moving back and forth on a straight path. The velocity of the bug is given by vt=t2-3t. Find the average acceleration o
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Answer:

2 unit/time²

Step-by-step explanation:

Given the equation:

v(t) =t^2-3t

At interval ; 1, 4

V(1) = 1^2 - 3(1)

V(1) = 1 - 3

V(1) = - 2

At t = 4

V(4) = 4^2 - 3(4)

V(4) = 16 - 12

V(4) = 4

Average acceleration : (final - Initial Velocity) / change in time

Average acceleration = (4 - (-2)) ÷ (4 - 1)

Average acceleration = (4 + 2) / 3

Average acceleration = 6 /3

Average acceleration = 2

3 0
2 years ago
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Answer:

1,3,5

Step-by-step explanation:

7 0
2 years ago
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(6-2.7h)+(-1.3j-4)<br><br> ?
SIZIF [17.4K]

Answer:

−2.7h−1.3j+2

Step-by-step explanation:

8 0
2 years ago
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