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inn [45]
2 years ago
11

The average adult human burns 2.00x20^3 kcal per day in energy. What is this rate in kJ per hour?

Chemistry
1 answer:
IRISSAK [1]2 years ago
7 0

Answer:

1.61 × 10⁶ kJ

Explanation:

The human burns energy so as to be healthy.

The amount of energy burnt per day by an adult human is 2 × 20³ kcal per day. Since there is 24 hours in a day, the amount of energy burnt per hour is 2 × 20³ × 24 = 48 × 20³ kcal per hour.

The conversion rate of kcal to kJ is 1 kcal = 4.184 kJ. Therefore converting the kcal per hour to kJ per hour gives:

48 × 20³ × 4.184 = 200.882 × 20³ kJ = 1.61 × 10⁶ kJ

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How long will it take 10.0 mL of Ne gas to effuse through a porous barrier if it has been observed that 125 minutes are required
cupoosta [38]

Answer:

88.8 minutes

Explanation:

Graham's law of diffusion relates rate of difusion by the following formula

Rate1 / rate 2 = √( Mass of argon / Mass of Neon)

Where rate = volume divided by time

Rate 1 = 10 ml / t1

Rate 2 = 10 ml / t2

Rate 1/ rate 2 = 10 ml / t1 ÷ 10 ml/ t2 = t2/ t1

t2/t1 = √(Mass of argon / mass of Neon) = √( 39.984/20.179)

125 / t1 = 1.4026

t1 = 125 / 1.4026 = 88.8 minutes

7 0
2 years ago
If you gently shake a carbon dioxide fire extinguisher, you will feel the presence of liquid within the extinguisher What condit
scoundrel [369]

When we wish to convert a gas to liquid we have to either

a) decrease temperature

b) increase pressure

In case of fire extinguisher the CO2 is found to be in liquid state, this is as the CO2 is pressurized at high pressure which keeps CO2 in liquid state

the ideal pressure and temperature conditions when CO2 gas can be converted to CO2 gas

Pressure = 5 - 73 atm

Temperature = -57  to 31 degree Celsius


6 0
2 years ago
Of the elements: b, c, f, li, and na. the element with the highest ionization energy is
padilas [110]
Carbon has the highest ionization energy as its energy 1086KJ\Mol and the rest are between 500 and 800. 
6 0
2 years ago
Tear gas has the composition 40.25% carbon, 6.19% hydrogen, 8.94% oxygen, 44.62% bromine. what is the empirical formula of this
andre [41]
<span>Calculating the moles and the moles ratio of the elements gives us the ratio of atoms in each element. Converting the percentage of element into grams 40.25% carbon = 40.25/100 = .4025 * 100 g of carbon = 40.25g of C 6.19% hydrogen = 6.19/100 = .0619 * 100g g of hydrogen = 6.19g of H 8.94% oxygen = 8.94/100 = .0819 * 100 g of oxygen = 8.19g of O 44.62% bromine = 44.62/100 = .4462 * 100 g of bromine = 44.62g of Br Converting the grams of element into moles (48.38 g C) (1 mol/ 12.10 g C) = 4.028 mol C (8.12 g H) (1 mol/ 1.008 g H) = 8.056 mol H (53.38 g O) (1 mol/ 16.00 g O) = 3.336 mol O (44.62g of Br)(0.012515018021626 moles) = 0.55842 mol Br Calculating the moles ratio of elements by dividing the small number of moles of an element 4.028 mol C /0.55842 = 7.2 mol C x 5 = 36 mol C 8.056 mol H / 0.55842 = 14.42 mol H = 72 mol H 3.336 mol O / 0.55842 = 5.97 mol O = 30 mol O 0.55842 mol Br / 0.55842 = 1mol Br = 5 mol Br So the empirical formula is (C6H12O5)6Br5</span>
8 0
2 years ago
Read 2 more answers
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
2 years ago
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