What is the quotient? StartFraction 2 m + 4 Over 8 EndFraction divided by StartFraction m + 2 Over 6 EndFraction StartFraction 2
4 Over (m + 2) squared EndFraction StartFraction (m + 2) squared Over 24 EndFraction Two-thirds Three-halves
2 answers:
Answer:
Step-by-step explanation
Given that,
(2m+4) / 8 / (m+2) / 6
Then,
(2m+4) / 8 ÷ (m+2) / 6
[(2m+4) / 8] × [6 / (m+2)]
Simply the 2m+4
[2(m+2) / 8] × [6 / (m+2)]
Then, m+2 cancel out
We are left with
(2 / 8) × 6
12 / 8 = 3 / 2
So, the answer is three-halves
The last option is correct,
Check attachment for better understanding.
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Answer:
And when we apply the limit we got that:
Step-by-step explanation:
Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"
We have the following formula in order to find the sum of cubes:
We can express this formula like this:
And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2
If we operate and we take out the 1/4 as a factor we got this:
We can cancel and we got
We can reorder the terms like this:
We can do some algebra and we got:
We can solve the square and we got:
And when we apply the limit we got that:
Answer:
AE = 43.2 units
Step-by-step explanation:
As per the given question image, it can be seen that in the
1.
2. is common to both the triangles.
3. Two angles are common, so the third angle is also equal to
.
All the three angles in the are equal to each other, hence the triangles are similar.
As per the property of similar triangles, the ratio of their sides will be equal.
AB : AC = AE : AD
AC = 88 units
BC = 55 units
AB = AC - AB = 33 units
Let side AE = units
Side AD = AE + ED
So, AD =
Using the ratio:
So, AE = 43.2 units