Factor 10e2 completely.

4/9 of students at school are boys if there are 2601 students at the school how many are girls

hram777 [196]

Answer:

1445

Step-by-step explanation:

2601*(9/9-4/9)

4 0

2 years ago

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Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni

trasher [3.6K]

For this case, the first thing we must do is define variables.

We have then:

t: the time in minutes

k: the number of kilometers

The relationship between both variables is direct.

Therefore, the function is:

$k (t) = c * t$

Where, "c" is a constant of proportionality.

To determine "c" we use the following data:

After running for 18 minutes, she completes 2 kilometers.

Substituting values:

$2 = c * 18$

Clearing c we have:

$c = \frac{2}{18}$

$c = \frac{1}{9}$

Then, the equation is given by:

$k (t) = \frac{1}{9} * t$

Answer:

An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

$k (t) = \frac{1}{9} * t$

7 0

2 years ago

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What type of triangle has side lengths 12, 13, and 2√3?

Travka [436]

Answer:

The triangle is an obtuse scalene triangle

Step-by-step explanation:

we know that

if $c^{2}=a^{2}+b^{2}$ --------> is a right triangle

if $c^{2}>a^{2}+b^{2}$ --------> is an obtuse triangle

if $c^{2}$ --------> is an acute triangle

where

c is the greater side

we have

$c=13\ units$

$a=12\ units$

$b=2\sqrt{3}\ units$

so

$c^{2}=13^{2}=169$

$a^{2}+b^{2}=12^{2}+(2\sqrt{3})^{2}=156$

so

$c^{2}>a^{2}+b^{2}$ -------> is an obtuse triangle

Remember that

The given triangle has three different length side

so

Is a scalene triangle

therefore

The triangle is an obtuse scalene triangle

4 0

2 years ago

For each of the questions below, a histogram is described. Indicate in each case whether, in view of the Central Limit Theorem,

denis-greek [22]

Solution :

a). This histogram is not a bell shaped.

Here we cannot use the theorem of the central limit as the histogram is being plotted by using 365 samples data values of the one sample.

b). This histogram may be bell shaped approximately since the sample size is large.

Here there are 50 sample each having a size of 500 and there is 50 sample proportions. The histogram shows sampling distribution of the sample proportion. Thus the central limit theorem can be used.

The histogram is approximately bell shaped as there is 50 samples of each having 500 size and an average of 50. Thus the central limit theorem can be used.

c). The histogram is not a bell shaped.

In this case central limit theorem cannot be used as the histogram is plotted by using 100 sample data values of one sample.

d). The histogram is a bell shaped since the sample size is large.

In this case 200 samples of each having a size of 50 and a data values of 50. The histogram here shows a sampling distribution of the sample proportion. Thus the central limit theorem can be used.

In the second also the histogram is of bell shaped as the sample size is large.

There are 200 samples of each sample having a size of 40 and they have 40 data values , i.e. sum of rolls.

e). It is not a bell shaped.

The histogram here is plotted using 100 sample data values having one sample. Therefore we cannot use the central limit theorem.

6 0

2 years ago

In the given the figure above, m∠BAC = 64° and m∠CBA = 56°. Part I: Find the m∠DEC. Part II: Explain the steps you took to arriv

Alex17521 [72]

since the triangles are similar

angle DEC = 60 degrees

3 angles inside a triangle equal 180 degrees

BAC = DCE = 64

CBA = EDC = 56

DEC = 180 -56 -64 = 60 degrees

used angle-angle theorem

6 0

2 years ago

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