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erica [24]
2 years ago
14

If the sales tax is 7% on all purchases, how much must you set aside for sales tax on $300? Show your work.

Mathematics
2 answers:
DIA [1.3K]2 years ago
7 0

Answer: $8.04

Step-by-step explanation: First you add on 7% to all of the amounts, then you get the new answer and subtract it by the old answer, finally you add up the subtracted amounts together. (Sorry if its wrong it tried my best)

GenaCL600 [577]2 years ago
4 0

Answer:

$321

Step-by-step explanation:

Because if you use a calculator u put in 300 + 7% you get 321

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A radio station spends 1/40 of each 24 hours on public service announcements. How much time is spent on public service announcem
mihalych1998 [28]
Start by calling the time spend on announcements 'A'. We can then set up an equation to represent the problem:

A=24hours \times \frac{1}{40}

and then solve by multiplication to get:

A=0.6hours

We could also convert this into minutes:

A=0.6hours \times \frac{60mins}{1hour} = 36mins


8 0
2 years ago
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Daniel has $600 in a checking account, has $12,000 in a savings account,
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Answer:

B

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600+12000+12000+35000=59600

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Is 14 quarter inches the most common measurement
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A baby wriggled so much that weighing him at the clinic was a problem. So the doctor held the baby and stood on a scale. Then th
Pepsi [2]
X = <span>weight of the baby.
y = </span>weight of the doctor.
z = weight of the nurse.

x + y = 78 so y = 78 - x
x + z = 69 so z = 69 - x
x + y + z = 142

substitute y = 78 - x and z = 69 - x into x + y + z = 142

x + y + z = 142
x +78 - x + 69 - x = 142
-x + 147 = 142
-x = - 5
 x = 5

answer

<span>the weight of the baby was 5 kg</span>
6 0
2 years ago
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Use lagrange multipliers to find the points on the given surface that are closest to the origin. y2 = 64 + xz
Inessa [10]
The distance between an arbitrary point on the surface and the origin is

d(x,y,z)=\sqrt{x^2+y^2+z^2}

Recall that for differentiable functions g(x) and h(x), the composition g(h(x)) attains extrema at the same points that h(x) does, so we can consider an augmented distance function

D(x,y,z)=x^2+y^2+z^2

The Lagrangian would then be

L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(y^2-64-xz)

We have partial derivatives

\begin{cases}L_x=2x-\lambda z\\L_y=2y+2y\lambda\\L_z=2z-\lambda x\\L_\lambda=y^2-64-xz\end{cases}

Set each partial derivative to 0 and solve the system to find the critical points.

From the second equation it follows that either y=0 or \lambda=-1. In the first case we arrive at a contradiction (I'll leave establishing that to you). If \lambda=-1, then we have

\begin{cases}2x+z=0\\2z+x=0\end{cases}\implies x=0,z=0

This means y^2=64\implies y=\pm8

so that the points on the surface closest to the origin are (0,\pm8,0).
8 0
2 years ago
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