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1 year ago

15

Rory works at a produce packing plant she packed 2172 strawberries last week and put them in a container with 8 strawberries in

each one how many containers of strawberries did Rory fill with 8 strawberries explains how you used the quotient and the remainder to awnser the question

1 answer:

mezya [45]1 year ago

8 0

Answer:

Number of containers = 271

Number of strawberries left = 4

Explanation:

Total number of strawberries = 2172.

Number of strawberries per container = 8

Number of strawberry container = Total number of strawberries/Number of strawberries per container.

Number of strawberry container = 2172/8

Refer the figure to see division,

Number of containers = 271

Number of strawberries left = 4

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In three hours, Company ABC can make X ball bearings. Company DEF can make X ball bearings in 4 hours. Company GHI can make X ba

amm1812

Answer:

<em>X ball bearings will be made in 1 hour and 20 minutes</em>

Step-by-step explanation:

<u>Proportions </u>

The proportions give us an important tool to easily solve common problems of any type. We know that:

Company ABC can make X ball bearings in 3 hours.

Company DEF can make X ball bearings in 4 hours.

Company GHI can make X ball bearings in 6 hours.

In one hour, each company can make

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DEF: X/4 ball bearings

GHI: X/6 ball bearings

Working together, they can make

$\displaystyle \frac{X}{3}+\frac{X}{4}+\frac{X}{6}$

ball bearings. Operating

$\displaystyle \frac{4X+3X+2X}{12}=\frac{9X}{12}=\frac{3X}{4}$

If they can make 3/4 of a ball bearing in one hour, then one complete ball bearing will need

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X ball bearings will be made in 1 hour and 20 minutes

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2 years ago

An element with mass 210 grams decays by 8.3% per minute. How much of the element is remaining after 15 minutes, to the nearest

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Answer:

57.2 g

Step-by-step explanation:

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2 years ago

circle o is inscribed in triangle rst such that it is tangent at points m,n, and p. if rp is 7, rt is 17 and sm is 5, then what

zloy xaker [14]

Answer:

The length of side st is 15.

Step-by-step explanation:

A tangent is a straigth line that touches a circle externally at a point on the circumference. Considering one of its properties that tangents from the same point to a fixed point outside a circle are equal.

Then,

/rn/ = /rp/

/tm/ = /tn/

/sm/ = /sp/

But, /rp/ = 7, /rt/ = 17 and /sm/ = 5.

Then,

/rt/ = /rn/ + /tn/

17 = 7 + /tn/ (∵ /rp/ = /rn/ = 7)

⇒ /tn/ = 10

Since /nt/ = 10, then /tm/ = 10 (/tm/ = /nt/)

So that,

/st/ = /sm/ + /tm/

= 5 +10

/st/ = 15

The length of side st is 15.

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1 year ago

The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a

maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

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Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

$\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}$

$\text{P(green swordtail)}=\dfrac{80}{140}$

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Therefore, the probability that the selected fish is a green swordtail is $\dfrac{4}{7}.$

B. We have to find the probability that the selected fish is male.

$\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}$

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Therefore, the probability that the selected fish is a male, is $\dfrac{3}{7}.$

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$\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}$

$\text{P(Male green swordtail)}=\dfrac{36}{140}$

$\text{P(Male green swordtail)}=\dfrac{9}{35}$

Therefore, probability that the selected fish is a male green swordtail is $\dfrac{9}{35}.$

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

$\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}$

$\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}$

$\text{P(Male or green swordtail)}=\dfrac{96}{140}$

$\text{P(Male or green swordtail)}=\dfrac{24}{35}$

Therefore, the probability the selected fish is either a male or a green swordtail is $\dfrac{24}{35}.$

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