For this problem, we plug in the <em>numbers for t</em> and the <em>appropriate letters for e</em> to the equation <em>e = 300 - 10t</em>.
a) a = 300 - 10(-2)
simplify: a = 300 + 20
simplify: a = 320 ft.
But, this is not a viable point because when t≤0, she doesn't move anywhere, thus, should consistently be 300 ft.
b) b = 300 - 10(3.5)
simplify: b = 300 - 35
simplify: b = 265 ft.
c) c = 300 - 10(30)
simplify: c = 300 - 300
simplify: c = 0 ft.
Answer:
22 m
Step-by-step explanation:
The distance traveled is ...
d = (1/2)at^2
where "a" is the magnitude of the acceleration.
d = (1/2)(11 m/s^2)(2 s)^2
d = 22 m
The car traveled 22 meters while braking.
1. lines j and k because they have the same slope.
2.d because -1/3 is the opposite slope of 3 and it passes through that point.
Answer:
The answer is C
Step-by-step explanation: Hope this helps!