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ololo11 [35]
2 years ago
3

LONDON (Reuters) - British scientists have devised a way of using graphene, which is the thinnest material in the world, to capt

ure and convert more light than previously, paving the way for advances in high-speed Internet and other optical communications.
In a study in the journal Nature Communication, the team -- which included last year's Nobel Prize-winning scientists Andre Geim and Kostya Novoselov -- found that by combining graphene with tiny, metallic structures, there was a 20-fold enhancement in the amount of light the graphene could capture and convert into electrical power.

Graphene is a form of carbon just one atom thick and yet 100 times stronger than steel.

"Many leading electronics companies consider graphene for the next generation of devices. This work certainly boosts graphene's chances even further," said Novoselov, a Russian-born scientist who with Geim won the 2010 Nobel Prize for physics for research work on graphene.

The researchers explained that due to unique properties of graphene, devices using it can be incredibly fast -- tens or potentially hundreds of times faster than communication rates in the fastest Internet cables currently in use.

Andrea Ferrari of Cambridge University's engineering department, who also worked on the team, said the findings show graphene's great potential in light-operated devices and in developing electronic devices that channel and control light. He said the combination of its special optical and electronic properties could be fully exploited
Which of the following statements summarizes the above article best?
A.
Engineers have found that graphene, which has been widely used in electronics for many years, degrades over time and will need to be replaced with copper.

B.
Researchers have discovered a new element called graphene, which will one day be used to build skyscrapers and advanced aircraft.

C.
A material called graphene has been proven to be stronger than steel and is now being widely used in electronic communications devices.

D.
Researchers working with the material graphene have made improvements to it that could one day lead to much faster electronic and light-operated devices.
Engineering
1 answer:
liraira [26]2 years ago
8 0

Answer:

C.

A material called graphene has been proven to be stronger than steel and is now being widely used in electronic communications devices.

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The legend that Benjamin Franklin flew a kite as a storm approached is only a legend—he was neither stupid nor suicidal. Suppose
Delicious77 [7]

Answer: 0.93 mA

Explanation:

In order to calculate the current passing through the water layer, as we have the potential difference between the ends of the string as a given, assuming that we can apply Ohm’s law, we need to calculate the resistance of the water layer.

We can express the resistance as follows:

R = ρ.L/A

In order to calculate the area A, we can assume that the string is a cylinder with a circular cross-section, so the Area of the water layer can be written as follows:

A= π(r22 – r12) = π( (0.0025)2-(0.002)2 ) m2 = 7.07 . 10-6 m2

Replacing by the values, we get R as follows:

R = 1.4 1010 Ω

Applying Ohm’s Law, and solving for the current I:

I = V/R = 130 106 V / 1.4 1010 Ω = 0.93 mA

7 0
2 years ago
A single crystal of a metal that has the FCC crystal structure is oriented such that a tensile stress is applied parallel to the
morpeh [17]

The magnitude of applied stress in the direction of 101 is 12.25 MPA and in the direction of 011, it is not defined.                                          

<u>Explanation</u>:        

<u>Given</u>:

tensile stress is applied parallel to the [100] direction

Shear stress is 0.5 MPA.

<u>To calculate</u>:

The magnitude of applied stress in the direction of [101] and [011].

<u>Formula</u>:

zcr=σ cosФ cosλ

<u>Solution</u>:

For in the direction of 101

cosλ = (1)(1)+(0)(0)+(0)(1)/√(1)(2)

cos λ = 1/√2

The magnitude of stress in the direction of 101 is 12.25 MPA

In the direction of 011

We have an angle between 100 and 011

cosλ = (1)(0)+(0)(-1)+(0)(1)/√(1)(2)

cosλ  = 0

Therefore the magnitude of stress to cause a slip in the direction of 011 is not defined.                                                                                                                                                                      

                                                                                   

                                                                                                                                                   

                                                                                                                                                             

5 0
2 years ago
Tech A says that as moisture levels increase in brake fluid, the boiling point of the brake fluid decreases. Tech B says that fi
dezoksy [38]

Answer: Both Technician A and B are correct.

Explanation:

Technicians A and B are both right about their diagnosis. The Society of Automotive Engineers performed extensive research on vehicle brake fluids and found that there is typically a 2% moisture content in the brake fluid after a year of operating a vehicle. And as the moisture content of the brake fluid rises, the boiling point of the brake fluid decreases as well.

4 0
2 years ago
Given an array of words representing your dictionary, you test words to see if it can be made into another word in dictionary. T
katen-ka-za [31]

Answer:

Detailed solution is given below:

8 0
2 years ago
The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel. Determine the magnitude of forc
Sonbull [250]

Answer:

Magnitude of force P = 25715.1517 N

Explanation:

Given - The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel.

To find - Determine the magnitude of force P so that the rigid beam tilts 0.015∘.

Proof -

Given that,

Diameter = 12 mm = 0.012 m

Length = 0.6 m

\theta = 0.015°

Youngs modulus of elasticity of 34 stainless steel is 193 GPa

Now,

By applying the conditions of equilibrium, we have

∑fₓ = 0, ∑f_{y} = 0, ∑M = 0

If ∑M_{A} = 0

⇒F_{BC}×0.9 - P × 0.6 = 0

⇒F_{BC}×3 - P × 2 = 0

⇒F_{BC} = \frac{2P}{3}

If ∑M_{B} = 0

⇒F_{AD}×0.9 = P × 0.3

⇒F_{AD} ×3 = P

⇒F_{AD} = \frac{P}{3}

Now,

Area, A = \frac{\pi }{4} X (0.012)^{2} = 1.3097 × 10⁻⁴ m²

We know that,

Change in Length , \delta = \frac{P l}{A E}

Now,

\delta_{AD} = \frac{P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9}  } = 9.1626 × 10⁻⁹ P

\delta_{BC} = \frac{2P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9}  } = 1.83253 × 10⁻⁸ P

Given that,

\theta = 0.015°

⇒\theta = 2.618 × 10⁻⁴ rad

So,

\theta =  \frac{\delta_{BC} - \delta_{AD}}{0.9}

⇒2.618 × 10⁻⁴ = (  1.83253 × 10⁻⁸ P - 9.1626 × 10⁻⁹ P) / 0.9

⇒P = 25715.1517 N

∴ we get

Magnitude of force P = 25715.1517 N

6 0
2 years ago
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