All categories

2 years ago

A cylinder has a base radius of 6m and a height of 16m. What is its volume in cubic m,

Mathematics

1 answer:

SpyIntel [72]2 years ago

8 0

Answer:

To the nearest tenth place, V = 1,810.3 m^3

Step-by-step explanation:

In this question, we are tasked with calculating the volume of a cylinder given its base radius and height.

Mathematically, the Volume can be calculated using the formula

V = pi * r^2 * h

where pi = 22/7 , r = 6m and h = 16m

Plugging these values, we have

V = 22/7 * 6^2 * 16

V = 22/7 * 36 * 16

V = 1,810.286 m^3

To the nearest tenth place, V = 1,810.3 m^3

You might be interested in

The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat

Greeley [361]

Answer:

1) $L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

2) $T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

3) $T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

$L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

Part 2

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

Part 3

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

Replacing we got:

$T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

8 0

2 years ago

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Ede4ka [16]

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

Step-by-step explanation:

We need to describes Catron’s error?

The steps are:

Step 1: (Negative 9) (2 + two-fifths)

Step 2: (Negative 9) (Negative 2) + (negative 9) (two-fifths)

Step 3: Negative 18 + (negative 9) (two-fifths)

Step 4: (negative 27) (two-fifths)

Solution: Negative StartFraction 54 over 5 EndFraction = Negative 10 and four-fifths

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

<u>Solving </u>

Solving the equation by removing the error:

Step 1: (Negative 9) (2 + two-fifths)

taking LCM of 2 and two-fifths (2/5)

Step 2: (Negative 9) (twelve-fifths)

Step 3: (Negative 9*twelve)-fifths

Step 4: Negative one hundred and eight- fifths

Solution: Negative StartFraction -108 over 5 EndFraction = Negative one hundred and eight- fifths

Keywords: Solving Expressions

Learn more about Solving Expressions at:

#learnwithBrainly

5 0

2 years ago

Read 2 more answers

The area of Norway is 24% more than the area of Colorado so Norway's area is-------% of Colorado's area

zhenek [66]

Possibly 124%.........

8 0

2 years ago

G=4cm-3m solve for m

adell [148]

m • (g4c - 3)

(1):g4 was replaced by g^4.

Pulling out like terms:

2.1:Pull out like factors:

g4cm - 3m = m • (g4c - 3)

Trying to factor as a Difference of Squares :

2.2:Factoring: g4c - 3

6 0

2 years ago

A right rectangular prism is 5 inches long, 12 inches wide, and 8 inches tall. The diagonal of the base is 13 inches.

coldgirl [10]

What is the question?

5 0

2 years ago