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dexar [7]
2 years ago
11

) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in

each of these four subnets are required to have the prefix 223.1.17/24. Also suppose that Subnet 1 is required to support at least 30 interfaces, Subnet 2 is to support at least 100 interfaces, Subnet 3 is to support at least 10 interfaces, Subnet 4 is to support at least 10 interfaces. Provide four network addresses (of the form a.b.c.d/x) that satisfy these constraints. Show all your work.
Computers and Technology
1 answer:
erik [133]2 years ago
4 0

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

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Explanation:

Electronic informed consent (eIC) may be used for seeking, confirming and documenting informed consent.

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Check your tire pressure every _____. A. month B. two months C. six months D. year
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Spark is electrical discharge in air, while air is mix of variety of gases what particles conduct electricity in gas
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1 year ago
Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
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Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate a
Taya2010 [7]

Answer:

// program in C++ to check leap year.

// include header

#include<iostream>

using namespace std;

// main function

int main() {

// variable

  int inp_year ;

  // ask user to enter year

  cout<<"Enter year:";

  // read year

  cin>>inp_year;

  // check year is leap or not

  if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))

  // if leap year , print leap year

     cout<<inp_year<<" is a leap year.";

  else

  // print not leap year

     cout<<inp_year<<" is not a leap year.";

  return 0;

}

Explanation:

Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not  leap year.

Output:

Enter year:1712                                                                                                            

1712 is a leap year.

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