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dexar [7]
2 years ago
11

) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in

each of these four subnets are required to have the prefix 223.1.17/24. Also suppose that Subnet 1 is required to support at least 30 interfaces, Subnet 2 is to support at least 100 interfaces, Subnet 3 is to support at least 10 interfaces, Subnet 4 is to support at least 10 interfaces. Provide four network addresses (of the form a.b.c.d/x) that satisfy these constraints. Show all your work.
Computers and Technology
1 answer:
erik [133]2 years ago
4 0

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

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Consider a disk that rotates at 3600 rpm. The seek time to move the head between adjacent tracks is 2 ms. There are 32 sectors p
jasenka [17]

Answer:

19.71 ms

Explanation:

The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.

Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms

Head movement time from track 8 to track  9 = seek time = 2 ms

rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms

The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms

3 0
2 years ago
What are the two main functions of user accounts in Active Directory? (Choose all that apply.) Allow users to access resources m
irina [24]

Answer:

method for user authentication to the network

Provide detailed information about a user

Explanation:

An in AD, a user account consists of all the information that includes user names, passwords, and groups. All these information defines a domain user in which a user account has membership access to. With the advanced features of Kerbos, mutual authentication in user accounts to a service is achieved.

3 0
2 years ago
Read 2 more answers
Megan has written the following rough draft for her assignment. Choose the correct way to complete each sentence. Sarah is creat
atroni [7]

Answer:

I. hatching

II. filter

Explanation:

Sarah is creating an image. She wants to achieve tonal effects with parallel lines by varying their densities and distribution patterns. She will use <u>hatching</u> to do this. She also wants to add special effects on the image. Therefore, she will use <u>filters</u>.

Hatching refers to an art technique in which parallel lines are used to shade by drawing them closely together.

Stippling is an art technique used in the making of patterns by using small dots.

Filters is a technique of changing image characteristics. It is used to change the picture characteristics & to add special effects to an image such as the shade, contrast, tone, brightness etc.

We therefore see that, <u>hatching</u> and <u>filter</u> are the correct answers respectively

3 0
2 years ago
Write a program whose input is two integers and whose output is the two integers swapped. Place the values in an array, where x
Aliun [14]

Answer:

import java.util.Arrays;

public class swap{

   public static void main(String []args){

       int [] arr = {2,4};

       swapValues(arr);

   }

   public static void swapValues(int[] values){

       int temp;

       System.out.println(Arrays.toString(values));

       temp=values[0];

       values[0]=values[1];

       values[1] =temp;

       System.out.println(Arrays.toString(values));

   }

}

Explanation:

In the program above, we created the method swapValues that receives an array of integers as parameters. in the method definition, we created a temp variable that is used to swapp the element at index 0 and index 1. Java's Arrays.to string method is used to print the array before and after the swap.

7 0
2 years ago
Write the prototype for a function named showSeatingChart that will accept the following two-dimensional array as an argument. c
barxatty [35]

Answer:

See explaination

Explanation:

void showSeatingChart(string seatingChart[20][40], const int ROWS, const int COLS){

for(int i = 0;i<ROWS;i++){

for(int j = 0;j<COLS;j++){

cout<<seatingChart[i][j]<<" ";

}

cout<<endl;

}

}

4 0
2 years ago
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