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2 years ago

Select all of the measurements that are equivalent to 528 meters.

SAT

2 answers:

IrinaK [193]2 years ago

8 0

<h3>Answer:</h3><h3>Answer A and Answer E are correct.</h3>

Explanation:

$528m = 52800cm \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.528km$

scZoUnD [109]2 years ago

6 0

A. 52,800 cm and E. 0.528 km

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If M is 20% less than N, what is the ratio of M to N?

dlinn [17]

Answer:

4:5

Explanation:

If M is 20% less than N, then we can think of M as being 80% of N. This gives us a ratio of 80:100 (80% to 100%, 20% less), which can then be simplified to the ratio 4:5.

Hope this helped!

8 0

2 years ago

5. The cost of my school exercise book was Rs. 10. Now she has to pay Rs

Annette [7]

<h2>Given :-</h2>

Cost of school exercise book was Rs. 10

Now , she had to pay Rs. 12 for it .

The increase percentage of price of that book .

<h2>Solution :-</h2>

$\underline{\bf{\dag} \:\bold{As\;we\;know\: that\: :}}$

$\sf Increase \% = \dfrac{(Value\;Increased)}{Initial\; Value} \times 100 \%$

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

→ Increase of Price = ( Rs. 12 - Rs. 10 )

⇒ Rs. 2

→ Initial Value = Rs. 10

Let's solve by putting the values in the formula !

$\sf \leadsto \dfrac{2}{10} \times 100 \%$

⇝2×10%

⇝20%

∴ The percent of increase in price of that school exercise book is 20 %

8 0

2 years ago

Soon Yi loves to bake, and she is making flaky pastry. Soon Yi starts with a layer of dough 222 millimeters (\text{mm})(mm)left

frozen [14]

Answer:

3 times

Explanation:

When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

$T(n)=T_0(1+r)^n$

Where:

Initial thickness, $T_0$ = 2mm

Growth factor, r =8%=0.08

We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

i.e When $T(n)\geq 2.5$ mm$

$2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9$