Two right-angled triangles are joined together to make a larger triangle ACD.
2 answers:
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Alright, so we are dealing with permutations. Permutations are the number of combinations in a specific order possible for the set.
There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:
number of elements in the subset
number of elements in the set
permutations of the set
There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.
Here's the math:
There are 24 permutations. I can prove this by showing you the model:
ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.
Hope this helps!
Answer: 24 passwords are possible
There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:
There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.
Here's the math:
There are 24 permutations. I can prove this by showing you the model:
ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.
Hope this helps!
Answer: 24 passwords are possible
Answer:
(–1.4, 1.5)
Step-by-step explanation:
The blue line and the purple line are the lines corresponding to the equations of interest. Their point of intersection is in the 2nd quadrant, so is nearest to ...
(–1.4, 1.5)
__
It can be useful to understand that for equations in standard form:
ax +by = c
the x- and y-intercepts are ...
- x-intercept: c/a . . . . value of x for y = 0
- y-intercept: c/b . . . . value of y for x = 0
__
For the equations of interest, the first has intercepts of ...
x=2/3, y=1/2 . . . . graphed line makes a 1st-quadrant triangle with the axes (blue line)
And the second has intercepts of ...
x=-1, y=-4 . . . . graphed line makes a 3rd-quadrant triangle with the axes (purple line)
Since the purple line has a steeper slope, the point of intersection of the lines will be in the 2nd quadrant. There is only one 2nd-quadrant answer choice: (-1.4, 1.5).
