How can you draw a net of a rectangular prism that has a height of 2 units and has bases that are 4 units long and 2 units wide?

Explain what you can tell just by comparing the symbols in a picture graph

IceJOKER [234]

The correct answer is:

What objects we're comparing.

Explanation:

In a picture graph, symbols are used to represent the data being displayed. For example, if we took a survey on the types of foods people preferred at a cookout, we could use a picture of a hamburger, a picture of a hot dot and a picture of a chicken leg.

We cannot tell anything about the amounts in the graphs just by comparing the symbols.

5 0

2 years ago

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The number of hurricanes hitting the coast of Florida annually has a Poisson distribution with a mean of 0.8. Answer the followi

slava [35]

Answer:

a) $P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]$

And we can find the individual probabilities like this:

$P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493$

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

$P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438$

And replacing we got:

$P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474$

b) $P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

Step-by-step explanation:

Let X the random variable that represent the number of hurricanes hitting the coast of Florida annualle. We know that $X \sim Poisson(\lambda=0.8)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda=0.8$

$E(X)=\mu =\lambda=0.8$

Part a

For this case we want this probability: $P(X>2)$

And for this case we can use the complement rule like this:

$P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]$

And we can find the individual probabilities like this:

$P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493$

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

$P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438$

And replacing we got:

$P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474$

Part b

Using the probability mass function we have:

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

3 0

2 years ago

Dan is watching The Birds in his backyard. Of the birds he watches, 9. Of them,or 45%, are sparrows. How many birds are in his b

ra1l [238]

If 9 of the sparrows is 45% of the birds in the backyard, 9/x = 45/100.

Cross multiply to get 9 * 100 = 45x; simplified is 900 = 45x or 20.

This means that there are 20 birds in the backyard. You can check this by dividing 9/20 which equals 45%

5 0

1 year ago

A tennis tournament starts with 117 players. If a player is eliminated after losing three matches, what is the least possible nu

ahrayia [7]

Step-by-step explanation:

If four players are left, then there are 117 – 4 = 113 players who have been eliminated.

3 0

2 years ago

The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo

oksian1 [2.3K]

Chaneece chooses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions.

y ≤ 40 – x, if x must be between 0 and 10, y must be between 20 and 40 it is true
proof
for x=0 and y=10, y ≤ 40 – x equivalent to 10<40-0=40 it is true
x=10, y=30, y ≤ 40 – x equivalent to 30=40-10=30 it is true

the answer is A) Yes, Chaneece found the correct solution.

5 0

2 years ago

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